Beta decay is exclusively the emission of electrons ... or its
oppositely charged relative, the positron ... from an atomic
nucleus.
Beta-minus is the emission of an electron, with a negative charge.
The change in the mass of the nucleus, if any, is minuscule.
The mass number of a nucleus is the sum of its protons and
neutrons, and the mass of an emitted electron is something
like 0.0005 the mass of one of those.
Answer:
/ Em₀ = 0.30
Explanation:
In this exercise we use the relationship of mechanical energy, kinetic energy and gravitational potential energy
K = ½ m v²
U = mgh
We calculate the mechanical energy at two points
Initial. Lower
Em₀ = K = ½ m v²
Highest finish
= U = mg and
Let's calculate
Em₀ = ½ m 3.6 2
Em₀ = m 6.48
= m 9.8 0.20
= m 1.96
The fraction of lost energy is
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
30% sun is converted into potential energy
It has several transformation possibilities
It is transformed into thermal energy of air and spores, since this energy cannot be recovered
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
brainly.com/question/15413360
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you are so wise how do you do it?
Answer:
local government agencies
