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Andre45 [30]
3 years ago
5

Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t

he point of ejection are 1 meter/second and 0.5 meters/second respectively, calculate the ratio of their horizontal distances of impact. 1:04 1:234 2:01 1.41:1 3:02
Physics
2 answers:
givi [52]3 years ago
8 0
For t1:

t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec

For t2:

t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec

Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)

d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m

Where:

d = hor. distance

ratio = d1:d2
= 0.319 : 0.225
=3.19 : 2.25

The answer is 3.19 : 2.25
LuckyWell [14K]3 years ago
3 0

Answer:

1.41 : 1

Explanation:

time required to reach the ground is given as

t = \sqrt{\frac{2h}{g}}

now we know that

h = 50 cm and h = 100 cm

so the ratio of time of two is given as

\frac{t_1}{t_2} = \sqrt{\frac{50}{100}}

\frac{t_1}{t_2} = \sqrt{\frac{1}{2}}

now the distance traveled by the object is given as

d = vt

now the ratio of the distance moved is given as

\frac{d_1}{d_2} = \frac{v_1t_1}{v_2t_2}

\frac{d_1}{d_2} = \frac{1}{0.5}\times \sqrt{\frac{1}{2}}

\frac{d_1}{d_2} = \sqrt 2 = 1.41 : 1

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Vedmedyk [2.9K]
Hello!

Vx = V0x + Ax*t
Vx = 18.1 + 2.4t

Let’s take time as 7.50 seconds:
Vx = 18.1 + 2.4*7.50
Vx = 18.1 + 18 = 36.1 m/s

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3 0
3 years ago
Starting from rest, a 2.1x10^-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exert
Rainbow [258]

Answer:

a) The flea's speed when it leaves the ground is v=1.88m/s

b) The flea move 18cm upward while it is pushing off

Explanation:

Hi

<u>Knwons</u>

Mass m=2.1\times 10^{-4} kg, Work W=3.7\times 10^{-4} J and Force F=0.41N

a) Here we are going to use W=\frac{1}{2} mv^{2}, so v=\sqrt{\frac{2W}{m} }= \sqrt{\frac{2(3.7\times 10^{-4} J)}{2.1\times 10^{-4} kg} }=1.88m/s

a) Here we are going to use W=mgh, so h=\frac{W}{mg}= \frac{3.7\times 10^{-4} J}{(2.1\times 10^{-4} kg)(9.8m/s^{2})} =0,1797m or 18cm approx.

7 0
3 years ago
How does the thickness of the lens affects its focal length plz ans this i will mark as brainliest
Oksanka [162]

Hello! :)

The focal length of the lens tells you how far away from the lens a focused image is created, if light rays approaching the lens are parallel. A lens with more “bending power” has a shorter focal length, because it alters the path of the light rays more effectively than a weaker lens. Most of the time, you can treat a lens as being thin and ignore any effects from the thickness, because the thickness of the lens is much less than the focal length. But for thicker lenses, how thick they are does make a difference, and in general, results in a shorter focal length.

Hope I helped and didn’t answer too late!

Good luck and stay COOL!

~ Destiny ^_^

5 0
3 years ago
If this decay has a half-life of 10.2 years, what mass of 60.8g carbon-14 will remain after 20.4 years
OLEGan [10]
20.4 years is 20.4/10.2 = 2 half-life cycles, which means a quarter of the starting mass or 15.2 g will remain after this time.
5 0
3 years ago
A 6,000N is applied to a formula one car that weighs 500kg. What is the car's acceleration?
Vesna [10]

Answer:

<h2>12 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question

f = 6000 N

m = 500 kg

We have

a =  \frac{6000}{500}  =  \frac{60}{5}  = 12 \\

We have the final answer as

<h3>12 m/s²</h3>

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