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MrRissso [65]
3 years ago
6

Help me on this online 24 game! You have to add, subtract, multiply, or divide any of these to equal 24!!!!!

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

24

Step-by-step explanation:

add 6+6 then 9+3 then both will equal 12 then add both to get 12 + 12 = 24

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Prism A is similar to Prism B. The volume of Prism A is 2720 cm³.
ZanzabumX [31]

Note that  the scale factor of B to A  is  (4 / 8)  =  1/2

So....the volume of B  =

Volume of A  *  (scale factor)^3  =

2720  *  (1/2)^3  =

2720 * 1/8  =

<span>340 cm^3</span>

<span>
</span>

<span>Hope this helps :)</span>

7 0
3 years ago
Read 2 more answers
T-SHIRTS You can buy 3 T-shirts for $24. Write a proportion that gives the cost
GrogVix [38]

7:56

Figure out what 7/3 is so you can multiply 24 by that number. Is is 2 1/3 so when you multiply 2 1/3 by 24 it gets you to 56 so the proportion is 7:56

8 0
2 years ago
Find x, the unknown side.<br><br> A) 4.6<br> C) 4.8<br> B) 5.4<br> D)3.5
MrMuchimi
Go ahead to do the trick
3 0
3 years ago
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The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
Please help me factor this!! Thanks!
Goryan [66]
We need to find two numbers that multiply to 24 (last coefficient) and add to 10 (middle coefficient). Through trial and error, the two values are 6 and 4

6 + 4 = 10
6*4 = 24

So we can break up the 10ab into 6ab+4ab and then use factor by grouping

a^2 + 10ab + 24b^2
a^2 + 6ab + 4ab + 24b^2
(a^2+6ab) + (4ab+24b^2)
a(a+6b) + 4b(a+6b)
(a+4b)(a+6b)

Therefore, the original expression factors completely to (a+4b)(a+6b)
5 0
3 years ago
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