Tell your instructor or teacher
Answer:
No information can be concluded from this observation alone the cloud is much cooler than hydrogen on Earth
Hi there!
a.
We can use the initial conditions to solve for w₀.
It is given that:

We are given that at t = 0, ω = 3.7 rad/sec. We can plug this into the equation:

Now, we can solve for sigma using the other given condition:

b.
The angular acceleration is the DERIVATIVE of the angular velocity function, so:

c.
The angular displacement is the INTEGRAL of the angular velocity function.




Convert this to rev:

d.
We can begin by solving for the time necessary for the angular speed to reach 0 rad/sec.

Evaluate the improper integral:



Convert to rev:

Explanation:
a) The angular speed omega is given defined as
omega = #rev/period = 1 rev/(0.6 s) = 1.7 rev/s
= (1.7 rev/s)×(2pi/rev) = 10.5 rad/s
b) v = (omega)×r
= (10.5 rad/s)(0.110 m)
= 1.16 m/s
Answer:
9.8 m/s
Explanation:
The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:

where
W is the work done
is the final kinetic energy of the cart
is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:

But the work is equal to the product between the pushing force F and the displacement, so

So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is
(1)
where m is the mass of the cart and v its final speed.
We can find the mass because we know the weight of the cart, 98.0 N:

Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:
