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1 year ago

An electric furnace that draws 40 amps with an applied voltage of 240 V will consume ________ watts.

Physics

1 answer:

irinina [24]1 year ago

5 0

The electric furnace will consume 9600 watt of power.

To find the answer, we need to know about the electric power.

<h3>What's the electric power?</h3>

Electric power is defined as the product of voltage and current.
Mathematically, power= V×I
Its si unit is watt.

<h3>What will be the power consumed by an electric furnace that draws 40A with an applied voltage of 240V?</h3>

The power = 240×40 = 9600 watt

Thus, we can conclude that the power consumption of the electric furnace is 9600 watt.

Learn more about the electric power here:

brainly.com/question/13080026

#SPJ4

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an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object b

Kay [80]

Answer:

333.3 m

Explanation:

Given

$m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2$

Potential energy = $\frac{2}{3}\ of\ Kinetic\ energy$ ......Equation(1)

We know that

Potential energy=mgh

Kinetic energy = $\frac{1}{2} mv^{2}$

Now From the Equation(1)

$mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m$

3 0

3 years ago

1. A car travels along a straight road to the east for 100 meters in 4 seconds, then go the west for 50 meters in 1 second.

Alla [95]

Answer:

a.Distance = 150 m

b. Displacement = 50 m

Time lapsed = 5 seconds

Explanation:

a. Distance is the change in the position of an object.

The distance covered by the car = 100 + 50

= 150 m

b. Since displacement is a vector quantity,

Displacement of the car = 100 - 50

= 50 m due east

c. Time elapsed is the time taken for the motion of the car starting from when its starts to when it stops.

Thus, the time elapsed = 4 + 1

= 5 seconds

4 0

2 years ago

You run<br> completely around a 400m track in<br> 80s. What was your average velocity?

dalvyx [7]

Answer:

V=?

S=400m

t=80s

V=S/t

V=400/80

V=5m/sec

6 0

3 years ago

A mass of 3.6 kg oscillate on a horizontal spring with a spring constant of 160 N/m.

Darya [45]

Answer:

48.7 J

Explanation:

For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.

In particular:

- The elastic potential energy is maximum when the system is at its maximum displacement

- The kinetic energy is maximum when the system passes through the equilibrium position

Therefore, the maximum kinetic energy of the system is given by:

$KE=\frac{1}{2}mv^2$

where

m is the mass

v is the speed at equilibrium position

In this problem:

m = 3.6 kg

v = 5.2 m/s

Therefore, the maximum kinetic energy is:

$KE=\frac{1}{2}(3.6)(5.2)^2=48.7 J$

6 0

3 years ago

Consider the circuit shown in the figure below. (Let R1 = 3.00 Ω, R2 = 8.00 Ω, and = 10.0 V.). . (a) Find the voltage across R1.

Goryan [66]

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8 0

3 years ago