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nexus9112 [7]
3 years ago
8

What is a substances specific heat

Physics
2 answers:
Romashka [77]3 years ago
7 0

Answer:

The amount of heat a substance can hold.

Explanation:

MrRa [10]3 years ago
4 0
It's the amount of heat you need to pump into 1 gram of the substance
in order to raise its temperature 1°C.

Different substances can have some wildly different values of specific heat.
The specific heat of water, potatoes, and rocks are especially high. That means
that those substances 'hold' a lot of heat ... which is why, before electric heating
pads were invented, rubber bags with these substances were used to warm up a
cold bed or to reduce the pain in a sore muscle.

Specific    Joules:
heat of:      per gm-°C

Lead          0.13
Copper      0.38
Iron           0.45
Aluminum   0.9
Water        4.2
Helium       5.2
Hydrogen 14.3

Don't quite understand the idea yet ?
Here's one way I like to think of it:

Here I have a soda straw, with the bottom end closed and some water in it.
How much water would you have to add to the straw to fill it 1 inch higher ?
Not much, right ?

OK.  Now, here I have a beer barrel that's maybe about half full of water.
How much water would you have to add to the barrel to fill it 1 inch higher ?
MORE than the soda straw, right ?

OK.  Now, here I have an olympic swimming pool with some water in it.
How much water would you have to add to the pool to fill it 1 inch higher ?
A lot ?  I agree.
How much ?  I don't know.
But definitely MORE than the straw or the barrel.

This is the way I understand specific heat:

-- The AMOUNT of water is like the heat-energy in the substance.
-- The DEPTH of the water is like the temperature of the substance.
-- The more water you pour into it, the deeper it gets.
-- The more heat you pour into it, the warmer it gets. 
-- But some substances are "wider" than others.
. . . . . Lead is very skinny, like the straw. 
          0.13 joule of heat added to a gram of it is enough to raise it 1°C.
. . . . . Water is a 'fatter' substance, like the barrel.
          You have to pour 4.2 joules into a gram of it, to raise it 1°C.
. . . . . Hydrogen is incredibly fat, like the pool.
          You have to pour 14.3 joules into 1 gram of it, to raise it 1°C.

==>  Hydrogen needs 110 times as much heat energy added as
Lead needs, to make 1 gram of each substance 1°C warmer than
they are now. 
The specific heat of Hydrogen is 110 times the specific heat of Lead !

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The famous cliff divers of Acapulco leap from a perch 35 m above the ocean. How fast are they moving when they reach the surface
Rus_ich [418]

1) 26.2 m/s

The mechanical energy of the divers at any point of their vertical motion is sum of the kinetic energy and the gravitational potential energy:

E=K+U = \frac{1}{2}mv^2 + mgh

where

m is the mass of the diver

v is the speed

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height above the water

When the diver is on the cliff, v = 0 (he is at rest), so K=0 and the initial mechanical energy is just potential energy:

E_i = mgh

where h=35 m is the height of the cliff.

When the diver hits the water above, h = 0, so U=0 and the final mechanical energy is just kinetic energy:

E_f = \frac{1}{2}mv^2

since the total mechanical energy is conserved, we have

E_i = E_f\\mgh = \frac{1}{2}mv^2

And solving the equation for v, we find the speed when they reach the surface of the water:

v=\sqrt{2gh}=\sqrt{2(9.8 m/s^2)(35 m)}=26.2 m/s

2) It is converted into thermal energy of the water

When the diver enters the water, he suddenly feels another force acting against the motion of the diver: the resistance of the water. The resistance of the water acts upward, slowing down the diver until he stops.

In this process, the speed of the diver (v) decreases, and therefore the kinetic energy of the diver decreases as well, until it becomes zero.

However, this does not mean that the conservation of energy has been violated. In fact, the kinetic energy of the diver has been converted into thermal energy of the molecules of water surrounding the diver.

8 0
3 years ago
True Or False for each question
Nana76 [90]

7 true

8 false

9 false

10 false

11 false

12 true

13 true

hope this helps!

6 0
3 years ago
The trajectory of a projectile always ________________. The trajectory of a projectile always ________________. is a straight li
jenyasd209 [6]

Answer:

curves downward, below the initial velocity vector.

Explanation:

Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).

Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.

6 0
3 years ago
Read 2 more answers
A horse began running due east and covered 25 km in 4.0 hr. What is the average velocity of the horse?
Darina [25.2K]
<span>B) 6.25 km/hr due east </span>
3 0
3 years ago
Read 2 more answers
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

3 0
3 years ago
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