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nexus9112 [7]
3 years ago
8

What is a substances specific heat

Physics
2 answers:
Romashka [77]3 years ago
7 0

Answer:

The amount of heat a substance can hold.

Explanation:

MrRa [10]3 years ago
4 0
It's the amount of heat you need to pump into 1 gram of the substance
in order to raise its temperature 1°C.

Different substances can have some wildly different values of specific heat.
The specific heat of water, potatoes, and rocks are especially high. That means
that those substances 'hold' a lot of heat ... which is why, before electric heating
pads were invented, rubber bags with these substances were used to warm up a
cold bed or to reduce the pain in a sore muscle.

Specific    Joules:
heat of:      per gm-°C

Lead          0.13
Copper      0.38
Iron           0.45
Aluminum   0.9
Water        4.2
Helium       5.2
Hydrogen 14.3

Don't quite understand the idea yet ?
Here's one way I like to think of it:

Here I have a soda straw, with the bottom end closed and some water in it.
How much water would you have to add to the straw to fill it 1 inch higher ?
Not much, right ?

OK.  Now, here I have a beer barrel that's maybe about half full of water.
How much water would you have to add to the barrel to fill it 1 inch higher ?
MORE than the soda straw, right ?

OK.  Now, here I have an olympic swimming pool with some water in it.
How much water would you have to add to the pool to fill it 1 inch higher ?
A lot ?  I agree.
How much ?  I don't know.
But definitely MORE than the straw or the barrel.

This is the way I understand specific heat:

-- The AMOUNT of water is like the heat-energy in the substance.
-- The DEPTH of the water is like the temperature of the substance.
-- The more water you pour into it, the deeper it gets.
-- The more heat you pour into it, the warmer it gets. 
-- But some substances are "wider" than others.
. . . . . Lead is very skinny, like the straw. 
          0.13 joule of heat added to a gram of it is enough to raise it 1°C.
. . . . . Water is a 'fatter' substance, like the barrel.
          You have to pour 4.2 joules into a gram of it, to raise it 1°C.
. . . . . Hydrogen is incredibly fat, like the pool.
          You have to pour 14.3 joules into 1 gram of it, to raise it 1°C.

==>  Hydrogen needs 110 times as much heat energy added as
Lead needs, to make 1 gram of each substance 1°C warmer than
they are now. 
The specific heat of Hydrogen is 110 times the specific heat of Lead !

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What type of nuclear decay releases energy but not a particle?
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I believe gamma decay but i may be wrong
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You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then lo
IgorC [24]

ANSWER:

F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.

STEP-BY-STEP EXPLANATION:

F(h) is Horizontal Force = 200 N

V is Speed = 2.4 m/s

The total weight increase by 42%

coefficient of rolling friction decrease by 19%

Since the velocity is constant so acceleration is zero; a=0

Now the horizontal force required to move the pickup is equal to the frictional force.

F(h) = F(f)

F(h) = mg* u

m is mass

g is gravitational acceleration = 9.8 m/s^2

200 = mg*u

Since weight increases by 42% and friction coefficient decreases by 19%

New weight = 1+0.42 = 1.42 = (1.42*m*g)

New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u

F(h) = (0.81μ) (1.42 m g)

       = (0.81) (1.42) (μ m g)

       = (0.81) (1.42) (200)

       = 230 N

4 0
3 years ago
Which describes a force acting on an object?
weeeeeb [17]

Answer:

Describing a Force:

To fully describe the force acting upon an object, you must describe both its magnitude and direction. Thus, 10 Newtons of force is not a complete description of the force acting on an object. 10 Newtons, downwards is a complete description of the force acting upon an object.

Explanation:

3 0
3 years ago
What is the momentum of a photon having the same total energy as an electron with a kinetic energy of 100 keV?
statuscvo [17]

Answer:

The momentum of the photon is 1.707 x 10⁻²² kg.m/s

Explanation:

Given;

kinetic of electron, K.E = 100 keV = 100,000 eV = 100,000  x 1.6 x 10⁻¹⁹ J = 1.6 x 10⁻¹⁴ J

Kinetic energy is given as;

K.E = ¹/₂mv²

where;

v is speed of the electron

K.E = \frac{1}{2}mv^2\\\\mv^2 = 2K.E \\\\v^2 = \frac{2K.E}{m} \\\\v = \sqrt{\frac{2K.E}{m}} \\\\but \ momentum ,P = mv\\\\(v)m = (\sqrt{\frac{2K.E}{m}})m\\\\P_{photon} =  (\sqrt{\frac{2K.E}{m_e}})m_e\\\\P_{photon} =  (\sqrt{\frac{2\times 1.6\times 10^{-14}}{9.11\times10^{-31}}})(9.11\times 10^{-31})\\\\P_{photon} = 1.707 \times 10^{-22} \ kg.m/s

Therefore, the momentum of the photon is 1.707 x 10⁻²² kg.m/s

6 0
3 years ago
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