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Allisa [31]
3 years ago
8

Which of the following accurately describes properties of valence?

Physics
2 answers:
tester [92]3 years ago
7 0
The answer is A), 'the smaller the number of electrons an atom has to borrow or to lend, the greater the activity of the atom'.
Troyanec [42]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

Valence electrons are defined as the electrons present in the outermost shell of an atom.

Smaller is need for valence electrons to be borrowed or to lend more is the reactivity of an atom.

For example, atomic number of fluorine is 9 and its electronic distribution is 2, 7.

So, it just needs one more electron in order to gain stability. Therefore, it will be highly reactive in nature.

Thus, we can conclude that the smaller the number of electrons an atom has to borrow or to lend, the greater the activity of the atom, accurately describes properties of valence.

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In a nuclear fusion reaction, the mass of the products is _____ the mass of the reactants.
JulijaS [17]

Answer:

more than

Explanation:

In a nuclear fusion reaction, the mass of the products is more than the mass of the reactants.

7 0
3 years ago
1. A sample consisting of 1.0 mol CaCO3 (s) was heated to 800oC when it is decomposed. The heating was carried out in a containe
ExtremeBDS [4]
Expansion work against constant external pressure: w=-pex Δ Δ V 3. The attempt at a solution . I tried following that. Because Vf>>Vi, and Vf=nRT/pex, then w=-pex x nRT/pex=-nRT (im assuming n is number of moles of CO2?). 1 mole of CaCO3 makes 1 mole of CO2, so plugging in numbers, I get 8.9kJ, although I dont use the 1 atm pressure at all
6 0
3 years ago
A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended
Alik [6]
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
k= \frac{F}{\Delta x}
where F is the force applied, and \Delta x is the stretch of the spring with respect to its equilibrium position. Using the data, we find
k= \frac{15 N}{3.0 cm}=5.0 N/cm

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
\Delta x =  \frac{F}{k}= \frac{30 N}{5.0 N/cm}=6 cm
4 0
3 years ago
Read 2 more answers
How does the eye control the amount of light entering it?​
Trava [24]

Answer:

Dilating the pupils.

3 0
3 years ago
Read 2 more answers
Please help!
andrew-mc [135]

Answer:

V=W/Q

107V= W/17C

= We= 107×17 J

= 1819 J

Explanation:

hope it helps

3 0
3 years ago
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