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Katena32 [7]
3 years ago
14

Headlights must be activated during times of darkness and when visibility is limited to what ?

Physics
1 answer:
garik1379 [7]3 years ago
7 0
Research says that if you have less than 1000 feet of visibility
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What is a pendulum in simple words and describe its parts
guajiro [1.7K]

Answer: A pendulum is an object hung from a fixed point that swings back and forth under the action of gravity.

Example: playground swing

8 0
3 years ago
The amount of time required for 2 successive wave crests to pass a fixed point is called wave ________.
mihalych1998 [28]
I believe this is known as wave period.
hope this helps!
7 0
3 years ago
An object of mass m is hung from a spring and set into oscillation. The period of the oscillation is measured and recorded as T.
sergejj [24]

Answer:\sqrt{2}T

Explanation:

Given

object of mass m is suspended from spring and set in oscillation with time Period T

We know Time period of a mass in oscillation is given by

T=2\pi \sqrt{\frac{m}{k}}

where k=spring constant

When mass m is replaced by a mass of 2 m time period is given by

T'=2\pi \sqrt{\frac{2m}{k}}

T'=\sqrt{2}\times 2\pi \sqrt{\frac{m}{k}}

T'=\sqrt{2}T

i.e. New time period becomes \sqrt{2} times of previous one

                         

7 0
3 years ago
You are a pirate working for dread pirate roberts. you are in charge of a cannon that exerts a force 10000 n on a cannon ball wh
KATRIN_1 [288]
<span>Answer: Let m = mass of cannon Then 10000 = ma a = 10000/m v^2 = u^2 + 2as v^2 = 0 + 2as 84^2 = 2(2.21)(10000/m) 84^2 m = 4.42(10000) m = 6.264172336 = 6.26 kg Part 2 Range = u^2sin(2x38)/g = 84^2sin(76)/9.8 = 698.6129229 = 698.6 m</span>
7 0
3 years ago
A 22-turn circular coil of radius 3.00 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plan
zloy xaker [14]

Answer:

23.5 mV

Explanation:

number of turn coil  'N' =22

radius 'r' =3.00 cm=> 0.03m

resistance = 1.00 Ω

B= 0.0100t + 0.0400t²

Time 't'= 4.60s

Note that Area'A' = πr²

The magnitude of induced EMF is given by,

lƩl =ΔφB/Δt = N (dB/dt)A

    =N[d/dt (0.0100t + 0.0400 t²)A        

    =22(0.0100 + 0.0800(4.60))[π(0.03)²]

     =0.0235

     =23.5 mV

Thus, the induced emf in the coil at t = 4.60 s is 23.5 mV

8 0
3 years ago
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