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Anna [14]
3 years ago
6

The trajectory of a projectile always ________________. The trajectory of a projectile always ________________. is a straight li

ne, in the same direction as the initial velocity vector follows a circular path curves downward, below the initial velocity vector at first goes up above the initial velocity vector and then curves down
Physics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

<h2>Curves downward. </h2><h2>At first goes up above the initial velocity and then curves down. </h2>

Explanation:

The trajectoy of a projectile is always a parabola concave down, beacuse it's movement is modeled by

y=v_{0} t-\frac{1}{2}gt^{2} (vertical motiion)

So, we know that quadratic equations are represented by parabolas.

So, the first answer is curves downward.

A simpler reason why it curves down is gravity, this acceleration makes the object to change is direction and velocity.

An important fact is that the inital and final point are at the same level, which means the initial velocity vector and the final velocity vector are equal.

However, notice that a projectile trajectory first moves up the initial vector and then moves down.

So, the second answer is at first goes up above the initial velocity and then curves down. However, it's important to notice that we are referring to the trajectory here, because higher positions of the projectile means a least velocity vector, because gravity is reducing the velocity.

jenyasd209 [6]3 years ago
6 0

Answer:

curves downward, below the initial velocity vector.

Explanation:

Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).

Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.

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3 years ago
1. Impulse is the product of force and distance. True or false?
daser333 [38]

Answer:

Explanation:

1. Impulse, I = F.t

  The statement impulse is the product of Force and distance is false.

2. F = m g

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   statement 2 is false.

3. Joule is equal to Newton times meter.

    Statement 3 is false.

4. Work done to lift an object is correct statement.

   Statement 4 is true.

5. Kinetic energy of an object is due to motion.

  Statement 5 is false.

6. Stopping distance is directly proportional to the square of velocity.

     If velocity is doubled, stopping distance is quadrupled.

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8 0
3 years ago
a runner increases her speed from 3.1 m/s to 3.5 m/s during the last 15 seconds of her run, what was her acceleration during her
Rama09 [41]
Acceleration = velocity/time
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5 0
3 years ago
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Put a ball on the floor what forces are acting on it
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Answer: Gravity

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8 0
3 years ago
A golf ball is struck with a five iron on level ground. it lands 100.0 m away 4.60 s later. what was the magnitude and direction
finlep [7]

consider the motion in x-direction

v_{ox} = initial velocity in x-direction = ?

X = horizontal distance traveled = 100 m

a_{x} = acceleration along x-direction = 0 m/s²

t = time of travel = 4.60 sec

Using the equation

X = v_{ox} t + (0.5) a_{x} t²

100 =  v_{ox} (4.60)

v_{ox} = 21.7 m/s


consider the motion along y-direction

v_{oy} = initial velocity in y-direction = ?

Y = vertical displacement  = 0 m

a_{y} = acceleration along x-direction = - 9.8 m/s²

t = time of travel = 4.60 sec

Using the equation

Y = v_{oy} t + (0.5) a_{y} t²

0 = v_{oy} (4.60) + (0.5) (- 9.8) (4.60)²

v_{oy} = 22.54 m/s

initial velocity is given as

v_{o} = sqrt((v_{ox})² + (v_{oy})²)

v_{o} = sqrt((21.7)² + (22.54)²) = 31.3 m/s

direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg

6 0
3 years ago
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