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Anna [14]
3 years ago
6

The trajectory of a projectile always ________________. The trajectory of a projectile always ________________. is a straight li

ne, in the same direction as the initial velocity vector follows a circular path curves downward, below the initial velocity vector at first goes up above the initial velocity vector and then curves down
Physics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

<h2>Curves downward. </h2><h2>At first goes up above the initial velocity and then curves down. </h2>

Explanation:

The trajectoy of a projectile is always a parabola concave down, beacuse it's movement is modeled by

y=v_{0} t-\frac{1}{2}gt^{2} (vertical motiion)

So, we know that quadratic equations are represented by parabolas.

So, the first answer is curves downward.

A simpler reason why it curves down is gravity, this acceleration makes the object to change is direction and velocity.

An important fact is that the inital and final point are at the same level, which means the initial velocity vector and the final velocity vector are equal.

However, notice that a projectile trajectory first moves up the initial vector and then moves down.

So, the second answer is at first goes up above the initial velocity and then curves down. However, it's important to notice that we are referring to the trajectory here, because higher positions of the projectile means a least velocity vector, because gravity is reducing the velocity.

jenyasd209 [6]3 years ago
6 0

Answer:

curves downward, below the initial velocity vector.

Explanation:

Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).

Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.

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isoceles

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What is 0.002 represented by
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Here, mA = 3.65 kg and mB = 7.05 kg. The string connecting the two objects is of negligible mass and the pulley is frictionless.
mr_godi [17]

Answer:

The magintude of the acceleration for both objects is 3.11m/s^2

Explanation:

Drawing a free body diagram on the two boxes we can analyze the system more easily.

we can take the acceleration going up as positive for reference purposes.

for mA let's suppose that is ascending so:

T_A-m_A*g=m_A*a

and for mB (descending):

T_B-m_B*g=-m_B*a

T_A=T_B

because the two boxes has the same acceleration because they are attached together:

m_B*g-m_B*a-m_a*g=m_a*a\\(m_B-m_A)*g=(m_a+m_B)*a\\a=\frac{(7.05kg-3.65kg)*9.8m/s^2}{3.65kg+7.05kg}\\\\a=3.11m/s^2

So the magintude of the acceleration for both objects is 3.11m/s^2

5 0
3 years ago
A 2 L balloon filled with gas is warmed from 280 K to 700 K. What is the volume of the gas after it is heated?
irakobra [83]

Answer:

New volume, v2 = 0.8L

Explanation:

<u>Given the following data;</u>

Original Volume = 2L

Original Temperature = 280K

New Temperature = 700K

To find new volume V2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

VT = K

\frac{V1}{T1} = \frac{V2}{T2}

\frac{V1}{T1} = \frac{V2}{T2}

Making V2 as the subject formula, we have;

V_{2}= \frac{V1}{T1} * T_{2}

V_{2}= \frac{2}{700} * 280

V_{2}= 0.0029 * 280

V2 = 0.8L

Therefore, the volume of the gas after it is heated is 0.8L.

7 0
3 years ago
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