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kolbaska11 [484]
4 years ago
15

The graph of a logarithmic function is shown below.

Mathematics
1 answer:
Dmitrij [34]4 years ago
3 0

Domain means all the x-values include in the graph.

In this case the graph starts including x-values at 0 and all x-values that are greater then 0.

In other words x can be zero or anything larger

Technically you would show this like so:

x ≥ 0

You use the inequality symbol with the bar underneath because you want to show that 0 is included in the domain. It faces away from the zero and towards the x because x can be larger then 0 not smaller.

I guess in this case you wouldn't be including 0 so your answer is:

B. x > 0

Hope this helped!

~Just a girl in love with Shawn Mendes

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TIMED QUESTION Which are the roots of the quadratic function f(b) = b2 – 75? Select TWO options.
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Step-by-step explanation:

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b=-5\sqrt{3} (b = Negative 5 StartRoot 3 EndRoot)

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The integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

<h3>What is Demand Function?</h3>

A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.

Here, given differential equation;

R'(x) = 599 - 0.21\sqrt{x}

we can also write this as;

\frac{d}{dx}R(x) = 599 - 0.21\sqrt{x}

d R(x) = (599 - 0.21\sqrt{x} ) dx

On integrating both sides, we get

\int\ d R(x) = \int\ (599 - 0.21\sqrt{x} ) dx

R(x) = 599x - 0.21 X \frac{2}{3}x^{3/2} + C

R(x) = 599x - 0.14x^{3/2} + C       ...........(i)

Also given, at x = 0, R(x) = 0, Put these values in equation (i), we get

0 = 0 - 0 + C

C = 0

Put the value of C in equation (i), we get

R(x) = 599x - 0.14x^{3/2}

Thus, the integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

Learn more about Demand Function from:

brainly.com/question/20564722

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