Answer:
A !!
Explanation:
because the equator is basically all the weather , so it cant be d , c , or b because in the artic is not hot and the desert cant be cold . so the answer is A
I need the graph to answer your question
Answer:
2CO + O₂ → 2CO₂ ΔH = -566 kj
Explanation:
Given data:
Energy evolved when 1 mole of CO react = 283 Kj
Energy evolved when 2 mole of CO react = ?
Solution:
Chemical equation:
2CO + O₂ → 2CO₂
It is given when one mole of CO react with oxygen 283 KJ energy is produced.
When 2 mole react,
2 ×-283 kj = -566 kj
Thermal equation:
2CO + O₂ → 2CO₂ ΔH = -566 kj
Answer:
The final temperature of the water mixture is 47.85°C
Explanation :
Given,
For Warm Water
mass = 10grams
Temperature = 105°C
For Cold Water
mass = 25grams
Temperature = 25°C
When a sample of warm water is mixed with a sample of cool water,
The energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:
<h3>Qlost = Qgain</h3>
However,
Q = (mass) (ΔT) (Cp)
Cp = Specific heat of water = 4.184 J/Kg°C
So,
(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)
We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using is FINAL temperature. This is what we are solving for.
The warmer water goes down from to 105°C to x, so this means its Δt equals 105°C − x. The colder water goes up in temperature, so its Δt equals x − 25℃
Substituting the values,
(10)( 105°C − x)(4.184) = (25)(x − 25℃)(4.184)
Solving for x, we get
x = 47.85°C
Therefore, The final temperature of the water mixture is 47.85°C.
Answer:
Final [B] = 1.665 M
Explanation:
3A + 4B → C + 2D
Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt
0.05600 M/s = 4 [B]/ 2.50 s
[B] = 0.035 M (concentration of B consumed)
Final [B] = initial [B] - consumed [B]
Final [B] = 1.700 M - 0.035 M
Final [B] = 1.665 M
