3 years ago

Thank you for all your help and support. Love you all.

Chemistry

2 answers:

iragen [17]3 years ago

8 0

Hello! Here is your answer for this question! ☺

Answer: C. 4MgCI2 --> Mg4+4CI2

Hope this helps you out! ☺

NeX [460]3 years ago

5 0

Answer:

the answer would be C. Thank you god bless you.

Explanation:

You might be interested in

How many moles of oxygen would be required to produce 5 mol of water? (Remember sig figs)

Vikki [24]

Answer:

Since moles are just "some number of particles", and since one O2 molecule contains enough oxygen for two H2O molecules, you need 2.5 moles of O2 for 5 moles of H2O.

7 0

3 years ago

Which type of system must exist for chemical equilibrium

larisa86 [58]

Answer: closed system.

Explanation:

4 0

3 years ago

for the reaction HCI+NaOH➡️NaCi+H2O, how many moles of hydrochloric acid are required to produce 150 g. of water?

Ne4ueva [31]

Answer: 8.33 mol of HCl (Hydrochloric Acid)

Explanation:

150 g H2O x __1 mol__ x __1 mol HCl__ = 8.33 mol of HCl

18.016 g 1 mol H2O

6 0

3 years ago

Use the table to answer the question

My name is Ann [436]

Answer:

Explanation:

hope the picture helps you to understand:)

4 0

2 years ago

Read 2 more answers

Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr

matrenka [14]

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = $6.023X10^{23}X0.691=4.16X10^{23}$

the percentage of heaviest Sn is 5.80%

So the total atoms of $Sn^{124}$ = 5.80% X $4.16X10^{23}$

Total atoms of $Sn^{124}$ = $2.41X10^{22}$ atoms

the mass of $Sn^{124}$ will be = $\frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g$

5 0

3 years ago