Answer:
The multiplicative identity property allows this to be true.
A function is differentiable if you can find the derivative at every point in its domain. In the case of f(x) = |x+2|, the function wouldn't be considered differentiable unless you specified a certain sub-interval such as (5,9) that doesn't include x = -2. Without clarifying the interval, the entire function overall is not differentiable even if there's only one point at issue here (because again we look at the entire domain). Though to be fair, you could easily say "the function f(x) = |x+2| is differentiable everywhere but x = -2" and would be correct. So it just depends on your wording really.
It’s B actually :) hope this helps
Step-by-step explanation:
We have
87+86+x
T is the total scores
n is number of tests done = 3
T/n is greater than or equal to 90
To get minimum test
T/n = 90
T = 90*n
= 90n
We solve for x
Remember n = 3
90x3 = 270
270 = 87+86+x
270 = 173+x
X = 270-173
X = 97
1.
X = 97
2.
You didn't add a value in your part b question. I used 80 though.
T/n < 80
T<80n
80x3= 240
T<240
87+86+x<240
X<240-173
X<67
X has to be less than 67 so we conclude that if x <=67 b grade will be lost.
