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weeeeeb [17]
3 years ago
9

IMPORTANT QUESTION ANSWER QUICK PLEASE!!!!!!

Physics
1 answer:
Flura [38]3 years ago
7 0
Ⓘ ⒷⒺⓁⒾⒺⓋⒺ ⒾⓉ ⒾⓈ Ⓒ ⒽⒶⓋⒺ Ⓐ ⒼⓄⓄⒹ ⒹⒶⓎ
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Scientific observations should be reported with bias as long as they benefit a scientist's employer
Ira Lisetskai [31]
False, there are always pros and cons to research
8 0
3 years ago
Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.
gogolik [260]

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

r=\frac {GM}{v^{2}}

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

3 0
3 years ago
The energy transferred between objects in contact as of temperature difference is called what?
slamgirl [31]

Answer:

Heat

Explanation:

4 0
2 years ago
Read 2 more answers
An electron and a proton have charges of an equal magnitude but opposite sign of 1.60 10-19 C. If the electron and proton in a h
MA_775_DIABLO [31]

The proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

<h3>What is the electrostatic force?</h3>

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by r is determined by the charge potency of each charge as well as the separation distance between them.

The electrostatic force is found as:

\rm F= \frac{Kq_1q_2}{R^2} \\\\ F= \frac{9 \times 10^ 9 \times 1.6 \times 10^{-19} \times -1.6 \times 10^{-19} }{(2.00\times 10^{-11})^2} \\\\\ F= 3.5 \times 10^{12} \ N

Hence, the proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

To learn more about the electrostatic force refer to the link;

brainly.com/question/9774180

#SPJ1

8 0
2 years ago
Un semáforo de 80N cuelga del punto medio de un cable de 30m tendido entre 2 postes. Halle la tensión en cada segmento del cable
olganol [36]

Answer:

T1 = T2 = 602.33 N

Explanation:

I attached an image of the forces diagram below.

The x component of the forces for this cases is:

\Sigma F_x=T_1cos\theta-T_2cos\theta=0\\\\T_1cos\theta=T_2cos\theta\\\\T_1=T_2

And the y components:

\Sigma F_y=T_1sin\theta+T_2sin\theta-W=0\\\\T_1=T_2=T\\\\\Sigma F_y=2Tsin\theta=W\\\\T=\frac{W}{2sin\theta}

The angle is calculated by using the information about the length of the cable and the vertical distance of the traffic light:

\theta=tan^{-1}(\frac{1}{15})=3.81\°

Thus, you obtain:

T=\frac{80N}{2(sin3.81\°)}=601.33N

hence, the tension in both segments of the cable is 602.33 N

3 0
3 years ago
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