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4 years ago

Which is an example of action and reaction forces?

Physics

2 answers:

Vlad [161]4 years ago

7 0

Hey there!

the answer is

C. a tennis racket striking a tennis ball

Thank you

Best regards

OFFICIALLYSAVAGE2003

suter [353]4 years ago

4 0

Answer:

Option (C)

Explanation:

According to Newton's third law 9f motion, for any action there is an equal and opposite reaction.

Both the forces acts on two different bodies.

Here ball gives an action on racket and racket gives reaction on ball.

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Mr. Galonski loves to use the electromagnetic spectrum. Create a scenario in his everyday life. Your scenario must include at le

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3 years ago

Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?

Eduardwww [97]

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3 years ago

Can someone pleaseee help me!!!

geniusboy [140]

Answer:You had a hard one. so for the 3 one the egg will not Evan float at all so no it will not

Explanation:a egg is a fragile thing that can not float.

7 0

4 years ago

If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?

bija089 [108]

Mass of fuel has the airplane took on = 167.89 kg

$\boxed{\boxed{\bold{Further~explanation}}}$

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

$\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

If we look at fuel capacity data such as Airbus which has a maximum capacity of 204, 5 liters then the mass of fuel it carries is

ρ = 0.821 gr / ml = 0.821 kg / l

mass = ρ . V

mass = 0.821 kg / l . 204.5 liters

mass = 167.89 kg

So the mass of fuel carried by aircraft is 167.89 kg

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Keywords: density, mass, volume, aircraft, fuel, derivative quantities

7 0

3 years ago

Read 2 more answers

A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi

docker41 [41]

32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8 t = 4
s = 6*t^2 + 2*t s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.

6 0

3 years ago