300 grams of ethanol is heated with 14640 Joules of energy to reach a final temperature of 30 °C. What was the initial temperatu

Question

3 years ago

11

re of the ethanol? The specific heat of ethanol is 2.44 J/g·°C.

2 answers:

nalin [4] · Answer 1 · 2022-12-05T09:59:11+03:00

nalin [4]3 years ago

8 0

Answer:

30°C

Explanation:

i just did it

levacccp [35] · Answer 2 · 2022-12-05T07:39:51+03:00

Answer:

10 °C

Explanation:

Applying

q = cm(t₂-t₁)............... Equation 2

Where q = heat energy, c = specific heat of ethanol, m = mass of ethanol, t₁ = initial temperature, t₂ = Final temperature.

Given: c = 2.44 J/g.°C, m = 300 g, q = 14640 J, t₂ = 30°C

Substitute into equation 2 and solve for t₁

14640 = 2.44×300(30-t₁)

14640 = 732(30-t₁)

732(30-t₁) = 14640

(30-t₁) = 14640/732

(30-t₁) = 20

t₁ = 30-20

t₁ = 10 °C