Question

An electron and a proton have charges of an equal magnitude but opposite sign of 1.60 10-19 C. If the electron and proton in a hydrogen atom are separated by a distance of 2.00 10-11 m, what are the magnitude and direction of the electrostatic force exerted on the electron by the proton

Answer 1

The proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

What is the electrostatic force?

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by r is determined by the charge potency of each charge as well as the separation distance between them.

The electrostatic force is found as:

$\rm F= \frac{Kq_1q_2}{R^2} \\\\ F= \frac{9 \times 10^ 9 \times 1.6 \times 10^{-19} \times -1.6 \times 10^{-19} }{(2.00\times 10^{-11})^2} \\\\\ F= 3.5 \times 10^{12} \ N$

Hence, the proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

To learn more about the electrostatic force refer to the link;

brainly.com/question/9774180

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