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stich3 [128]
4 years ago
12

A student mixed together 8 g of sugar, 5.20 g of salt

Chemistry
2 answers:
maw [93]4 years ago
7 0

its C) 113.21g

u just add all the masses

stich3 [128]4 years ago
4 0
When adding values, the rules for the significant figures say that your answer should have as much decimal digits as the number with the least digits after the comma. In this case, 0 as ‘8 g’ has no decimals. For a multiplication you should look at significant numbers. If you would multiply these values, the answer would only be allowed to have 1 digit multiplied by a power of 10. The answer for this question is therefore 113 g as you follow the rules for addition (decimals).
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A student’s experiment showed that her egg gained mass overnight with the vinegar and distilled water. She had about a +1% chang
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3 years ago
Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.
Lelechka [254]

Explanation:

(a). The given data is as follows.

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Volume of 4 glass of water = 220 \times 4 = 880 ml

We known that density of water is 1 g/ml.  Therefore, calculate the mass of water as follows.

       Mass of water = 880 ml \times 1 g/ml

                               = 880 gm

                               = 0.88 Kg               (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

            Q = mC \Delta T

\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C

Putting the given values into the above formula as follows.

         Q = mC \Delta T

             = 0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C

             = 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b).      As we know that the heat of fusion of ice is 333 J/g.

So, energy required for 8.4 \times 10^{2} g or 840 g is as follows.

          333 \times 840 = 279.72 kJ

Heat capacity of water= 4.184 J/g^{o}C

Now, heat energy will be as follows.

           Q = 4.184 \times 840 g \times 37^{o}C

               = 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

                                                  = 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ  of heat.

6 0
4 years ago
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