Which is a compound? A) Kr B) O2 C)Cl2 D)CuF2

Predict the splitting pattern for each of the labeled hydrogens in the following molecules. Assume that all coupling constants a

Ghella [55]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

b) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

c) The IUPAC name is Butan-2-ol

Explanation:

Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.

According to that for molecule 1 as shown on the second uploaded image

For Proton Ha, number of non equivalent protons n= 2

Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

Considering the second question for Molecule 2 as shown on the third uploaded image

For Proton Ha, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

For Proton Hb, number of non equivalent protons n= 3

Splitting pattern for Hb= 3+1=4 , Quartet

For Proton Hc, number of non equivalent protons n= 3

Splitting pattern for Hc= 3+1=4 , Quartet

For Proton Hd, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

Considering the third question

The name of the given molecule is gotten according to longest carbon chain = 4 (Prefix 'Butan')

Functional group = -OH (Suffix 'ol') at C-2

The IUPAC name is Butan-2-ol

3 0

3 years ago

Aluminum foil, cast iron pans, copper pipes, graphite, and sea water can be classified as

Korolek [52]

answer

C) is the answer ⟵(๑¯◡¯๑)

3 0

3 years ago

Read 2 more answers

In the b-pleated sheet conformation A. there are hydrogen bonds perpendicular to the direction of the polypeptide chain.B. the p

inysia [295]

Answer:

D. all of these

Explanation:

Proteins are chains of amino acids (polypeptides) that adopt a specific conformation in space. To adopt this conformation, the amino acid chains fold locally and regularly, forming what is known as secondary structures. Mainly, there are two types of secondary structures: the α-helix and the β-pleated sheet.

In the α-helix, the polypeptide chain is spirally wound on itself. This structure is maintained thanks to hydrogen bonds between the carboxyl group of an amino acid and the amino group of the fourth amino acid that follows in the chain.

In the β-pleated sheet the polypeptide skeleton is almost extended in a zig zag shape and stability is achieved by the association of two or more peptide chains next to each other by hydrogen bonds between the amino and carboxyl groups of the peptide bond between adjacent chains. For this reason, hydrogen bonds are almost perpendicular to amino acid chains. In the image Bsheet this phenomenon can be observed.

Usually, the chains are drawn with an arrow to indicate the direction of the polypeptide chain from the amino group to the terminal carboxyl. Thus, adjacent chains of a beta sheet can be oriented in the same direction (parallel beta sheets), or in opposite directions (antiparallel beta sheets). The same folded beta sheet can have parallel and antiparallel chains. The image Bsheet 2 shows parallel and antiparallel chains.

4 0

3 years ago

How many moles of carbon dioxide are produced when 22.8g of butane react

Juliette [100K]

Butane undergoes combustion to produce carbon dioxide and water, expressed in the following reaction C4H10 (g) + O2 (g) → 4CO2 (g) + 5H2O (g) . 1 mole of butane is to 4 moles of CO2. In this case, when 22.8 grams of butane or 0.393 moles of it, 69.18 grams of carbon dioxide is produced

4 0

3 years ago

Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.

Shtirlitz [24]

Answer:

(a) $pH = -Log (0.1M) = 1$

(b) $pH = -Log (10^{-13}M) = 13$

(c) $pH = -Log (3x10^{-3}M) = 2.5$

(d) $pH = -Log (4.93x10^{-10}M) = 9.3$

(e) $pH = -Log (5^{-7}M) = 6.3$

Explanation:

To calculate de pH of an acid solution the formula is:

$pH = -Log ([H^{+}]) = 1$

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

$K_{w} =[H^{+} ][OH^{-}]=10^{-14}$