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VARVARA [1.3K]
3 years ago
14

A waitperson carrying a tray with a platter on it tips the tray at an angle of 12° below the horizontal. If the gravitational fo

rce on the platter is 5.0 N, what is the magnitude of the force parallel to the tray that tends to cause the platter to slide down the tray? (Disregard friction.)
a.

0.42 N

c.

4.9 N
b.

1.0 N

d.

5.0 N
Physics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

The answer is 1.0 N

Explanation:

inclination of tray=12^{\circ}

gravitational Force=5 N

Now this gravitational force has two component i.e.

5\sin \theta  is parallel to the tray =1.039 N

5\cos \theta  is perpendicular to the tray =4.890 N

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A shopper walks westward 5.4 meters and then eastward 7.8 meters
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Answer:

13.2 meters

Explanation:

(5.4) + (7.8)

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A 40 kg boy is moving upwards upwards in a lift with an acceleration of 2 m /s ^2 what would be the weight felt by him if measuu
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Answer:

<h2> 48kg</h2>

f = ma \\

w \:  =  \frac{f}{g}  \\

Explanation:

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3 years ago
Tension force ........... throughout a string that changes direction over a pulley.
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4 years ago
A movie star catches a paparazzi reporter snapping pictures of her at home and claims that he was trespassing. He, of course den
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Answer:

44.755 m

Explanation:

Given:

Height of the movie star, H = 1.75 m = 1750 mm

Height of the image, h = - 8.25 mm

Focal length of the camera = 210 mm

Let the distance of the object i.e the distance between camera and the movie star be 'u'

and

distance between the camera focus and image be 'v'

thus,

magnification, m = \frac{\textup{h}}{\textup{H}}

also,

m = \frac{\textup{-v}}{\textup{u}}

thus,

\frac{\textup{-v}}{\textup{u}}=\frac{\textup{h}}{\textup{H}}

or

\frac{\textup{-v}}{\textup{u}}=\frac{\textup{-8.25}}{\textup{1750}}

or

\frac{\textup{1}}{\textup{v}}=-\frac{\textup{1750}}{\textup{-8.25}}\times\frac{1}{\textup{u}}  ....................(1)

now, from the lens formula

\frac{\textup{1}}{\textup{f}}=\frac{\textup{1}}{\textup{u}}+\frac{1}{\textup{v}}

on substituting value from (1)

\frac{\textup{1}}{\textup{210}}=\frac{\textup{1}}{\textup{u}}+-\frac{\textup{1750}}{\textup{-8.25}}\times\frac{1}{\textup{u}}

or

\frac{\textup{1}}{\textup{210}}=\frac{\textup{1}}{\textup{u}}(1 -\frac{\textup{1750}}{\textup{-8.25}})

or

u = 210 × ( 1 + 212.12 )

or

u = 44755.45 mm

or

u = 44.755 m

6 0
4 years ago
How many neutrons are needed to initiate the fission reaction shown?
nalin [4]

Answer: One neutron

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Sum up the mass numbers on the right 99 + 135 + 2 = 236.

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