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VARVARA [1.3K]
3 years ago
14

A waitperson carrying a tray with a platter on it tips the tray at an angle of 12° below the horizontal. If the gravitational fo

rce on the platter is 5.0 N, what is the magnitude of the force parallel to the tray that tends to cause the platter to slide down the tray? (Disregard friction.)
a.

0.42 N

c.

4.9 N
b.

1.0 N

d.

5.0 N
Physics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

The answer is 1.0 N

Explanation:

inclination of tray=12^{\circ}

gravitational Force=5 N

Now this gravitational force has two component i.e.

5\sin \theta  is parallel to the tray =1.039 N

5\cos \theta  is perpendicular to the tray =4.890 N

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A man walks 40 m North, then 70 m East and then 40
Anastasy [175]

Answer:

Displacement = 70 m towards east

Explanation:

Displacement is the shortest distance between the two points.

Let us say that he starts at the point O and travels in a path ABC.

If we join the initial and final point of the path travelled by him, it will give the displacement of the man.

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In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B

Displacement = Distance from A to B

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Solve: A car travels 2 km North , 10 km East, then 3 km West. pythagorean theorem
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________b_____ 7 km east

|

| 2km north.

|a

|

°

pythagorean theorem : ✓a² + b² = c²

c² = a² + b² = 4 + 49 = 53

c = ✓53 km

displacement = c = ✓53 km

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