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anastassius [24]
2 years ago
13

7. What is the velocity of an object that has a mass of 4.5 kilograms and

Physics
1 answer:
labwork [276]2 years ago
7 0

Answer:

266.66 m/s

Explanation:

p=mv

1200=4.5v

v=266.66 m/s

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Diffraction occurs when waves _____ after passing through an opening
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The answer to your question is A
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3 years ago
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What is a centripetal acceleration of a point on a bicycle wheel of a radius of 0.70 m when a bike is moving 8.0 m/s
Furkat [3]

Answer:

The acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

Explanation:

The centripetal acceleration acts on a body when it is performing a circular motion.

Here, a point on the bicycle is performing circular motion as the rotation of the wheel produces a circular motion.

The centripetal acceleration of a point moving with a velocity v and at a distance of r from the axis of rotation is given as:

a=\frac{v^2}{r}

Here, v=8\ m/s,r=0.70\ m

∴ a=\frac{8}{0.70}=11.43\ m/s^2

Therefore, the acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

3 0
3 years ago
List examples of how the Bill of Rights protects you:<br> .<br> .<br> .<br> .<br> .
Naya [18.7K]

guaranteeing freedom of speech, press, assembly, and exercise of religion

4 0
2 years ago
Spiderman, whose mass is 74.0 kg, is dangling on the free end of a 11.0-m-long rope, the other end of which is fixed to a tree l
Anestetic [448]

Answer:

W = -1844.513 J

Explanation:

GIVEN DATA:

mass of spider man is m  74 kg

vertical displacement if spider is 11 m

final displacement  =  11 cos 60.6 =  - 6.753 m

change in displacement is  = -6.753 - (-11) = 4.25 m

gravity force act on spiderman is f = mg = 74 × 9.8 = 725.2 N

work done by gravity is W = F \delta r cos\theta

W = 725.2 \times 4.25 \times cos 180

where 180 is the angle between spiderman weight and displacement

W = -1844.513 J

7 0
3 years ago
If you walk 1.2 km north and then 1.6 km east, what are the magnitude and direction of your resultant displacement?
SVETLANKA909090 [29]

B

Assume north and east as two sides of a right angled triangle. magnitude of the distance is then given by the length of the hypotenuse which is \sqrt{a^2 + b^2}

where a = 1.2 km north

and b = 1.6 km east

magnitude = 2 km

Direction is given by the angle between them, that is atan(a/b) = 36.86 deg north of east = 53.1 deg east of north.

8 0
3 years ago
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