The average speed of the ant is 0.276 cm/s and the average velocity is 0.136 cm/s.
The correct answer is option D.
In the given graph, we can deduce the following;
- the total time of the motion, = 1 mins + 45 s = 60 s + 45 s = 105 s
The average speed of the ant is calculated as;

The total distance from the graph is calculated as follows;
- first horizontal distance from 2 cm to 8 cm = 8 - 2 = 6 cm
- first upward distance from 3 cm to 5 cm = 5 - 3 = 2 cm
- second horizontal distance from 8 cm to 6 cm = 8 - 6 = 2 cm
- second upward distance from 5 cm to 12 cm = 12 - 5 = 7 cm
- third horizontal distance from 6 cm to 13 cm = 13 - 6 = 7 cm
- fourth downward distance from 12 cm to 9 cm = 3 cm
- final horizontal distance from 13 cm to 15 cm = 2cm
The total distance = (6 + 2 + 2 + 7 + 7 + 3 + 2) cm = 29 cm

The average velocity is calculated as the change in displacement per change in time.
The displacement is the shortest distance between the start and end positions.
- This shortest distance is the straight line connecting the start and end position. Call this line P
- From the end position at x = 15 cm, draw a vertical line from y = 9 cm, to y = 3 cm. The displacement = 9 cm - 3 cm = 6 cm
- Also, draw a horizontal line from start at x = 2 cm to x = 15 cm. The displacement = 15 cm - 2 cm = 13 cm
Notice, you have a right triangle, now calculate the length of line P.
↓end
↓
↓ 6cm
↓
start -------------13 cm------------
Use Pythagoras theorem to solve for P.

The average velocity of the ant is calculated as;

Thus, the average speed of the ant is 0.276 cm/s and the average velocity is 0.136 cm/s.
Learn more here: brainly.com/question/589950
Answer:
Planets are bodies of rock or gas that are named after ancient gods.
Asteroids and Meteoroids are made of rock or metal, which often collide with Earth.
The terrestrial planets are more like the Earth.
The Juno spacecraft is exploring the planet Jupiter.
Explanation:
The planets and other stars in our solar system were similarly baptized. The planets were named after ancient gods. Other stars were baptized with names chosen by scientists or according to their peculiarity. Most of the planets were baptized by ancient Chinese astronomers, and later, by Babylonians. But over time different civilizations changed the names of the planets.
An asteroid is a smaller body in the solar system, usually on the order of just a few hundred kilometers. Meteoroids, in turn, are fragments of rocks that form from comets and asteroids. The luminous effect is produced when fragments of celestial bodies ignite in contact with the Earth's atmosphere due to friction. Both asteroids and meteoroids are made of rock or metal, which often collide with Earth.
The terrestrial planets are the most similar to the earth. These planets are those formed mainly by rocks and metals, have a solid surface without the incidence of rings, as is the case with Mercury, Venus and Mars.
The Juno spacecraft is exploring the planet Jupiter. This probe has already given us several unprecedented discoveries about the largest gas giant in the Solar System, in addition to sending us sensational images showing the complex and beautiful atmosphere of the planet.
B) All nonzero digits are significant.
Answer:
<em>The first choice (32m/s) is the closest to the answer</em>
Explanation:
The magnitude of a vector is the distance between the initial and the end point of the vector.
Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.
Calculate the magnitude of the velocity:




The first choice (32m/s) is the closest to the answer