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zalisa [80]
3 years ago
7

Find the velocity in m/s of a swimmer who swims 110m toward the shore in 72 s

Physics
1 answer:
Sladkaya [172]3 years ago
8 0
1.5 m/s toward shore 

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Answer:

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Explanation:

Let's analyze this exercise we can use the basic kinematics relationships to love the initial velocity and the acceleration we can look for from Newton's second law where force is gravitational attraction.

    F = m a

    G m M / x² = m dv / dt = m dv/dx  dx/dt

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    GM dx / x² = v dv

We integrate

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We evaluate between the lower limits where x = Re = 6.37 10⁶m  and the velocity v = vo and the upper limit x = 2.50 10⁸m  with a velocity of v = 8.50 10³ m/s

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    72.25 10⁶ - v₀² = -1.213  10⁸

    v₀² = 72.25 10⁶ + 1,213 10⁸

    v₀² = 193.6 10⁶

    v₀ = 13.9 10³ m / s

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