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3 years ago

A(n) is built only after an engineer can prove sound design through structural analysis.

Engineering

2 answers:

prohojiy [21]3 years ago

7 0

Use Brainly ..........

zhuklara [117]3 years ago

4 0

Answer:

Prototype

Explanation:

You might be interested in

Early manufacturing, done for personal use, has been called?

AnnyKZ [126]

Answer:

self made tech yes

Explanation:

its made by yourself

7 0

3 years ago

Cryogenic liquid storage. Liquid oxygen is stored in a thin-walled spherical container, 96 cm in diameter, which is further encl

Anvisha [2.4K]

Answer:

The answer is "26.55 V"

Explanation:

Given values:

$d_i= 0.96m\\d_o= 1m\\\epsilon = 0.05\\T_0= 280k\\T_i= 95k\\$

For Answer (a) please find the attachment.

Answer (b):

$q_{i-0}= \frac{\sigma (T_{0}^4)-(T_{i}^4)}{\frac{1-\epsilon i }{\epsilon_{i} A_{i}}+ \frac{1 }{\ f_{i o} A_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0} A_{0}}}$

$f_{i0}= 1 \ it \ is \ fully \ inside \ the \ large \ sphero \\$

$q_{i-0}= \frac{\sigma A_i (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} - 1+ 1 +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times \frac{A_i}{A_0}}\\\\q_{i-0}= \frac{\sigma A_i (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times (\frac{d_i}{d_0})^2}\\\\q_{i-0}= \frac{\sigma (\pi d^2_i) (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times (\frac{r_i}{r_0})^2}\\\\$

$q_{i-0}= \frac{5.67 \times 10^{-8} \times 3.14 \times 9.62 \times 9.62 \times (280^4-94^4)}{\frac{1 }{0.05} +\frac{1-0.05}{0.05} \times (\frac{0.96}{1})^2}\\\\\ After \ solve the \ equation \ the \ answer \ is:\\\\q_{i-0} = 26.55 \ V$

4 0

3 years ago

Craig is buying a clamp and wants to know how tightly it will hold object. What measurement is he concerned with?

olchik [2.2K]

The correct answer is b pascal

8 0

2 years ago

A steam turbine has isentropic efficiency of 0.8. Isentropically, it is supposed to deliver work of 100 kW. What is the actual w

trapecia [35]

Answer:

80 kW; 11 kW; 8 kW; 0.6

Explanation:

Part 1

Isentropic turbine efficiency:

$\eta_t = \frac{\text{Real turbine work}}{\text{isentropic turbine work}} = \frac{W_{real}}{W_s}$

$W_{real} = \eta_t*W_s$

$W_{real} = 0.8*100 kW$

$W_{real} = 80 kW$

Part 2

Coefficient of performance COP is defined by:

$COP = \frac{Q_{out}}{W}$

$Q_{out} = W*COP$

$Q_{out} = 5 kW*2.2$

$Q_{out} = 11 kW$

Part 3

(a)

Energy balance for a refrigeration cycle gives:

$Q_{in} + W = Q_{out}$

$3 kW + 5 kW = Q_{out}$

$8 kW = Q_{out}$

(b)

$COP = \frac{Q_{in}}{W}$

$COP = \frac{3 kW}{5 kW}$

$COP = 0.6$

3 0

4 years ago

Consider a composite wall that includes an 8-mm-thick hardwood siding, 40-mm by 100-mm hardwood studs on 0.65-m centers with gla

mel-nik [20]

Answer:

total resistance = 0.18414 K/W

Explanation:

given data

length L = 8 mm

siding = 40 mm

siding = 100 mm

studs = 0.65-m

paper faced, 28 kg/m³

gypsum layer = 12-mm

to find out

thermal resistance associated with a wall that is 2.5 m high by 6.5 m wide (having 10 studs, each 2.5 m high)

solution

we will apply here resistance formula that is

resistance = $\frac{L}{Ka*A}$ ...................1

here L is length and Ka is thermal conductivity and A id area

thermal conductivity of hard wood siding = 0.94 W/m-K

and thermal conductivity of hard wood stud = 0.16 W/m-K

and thermal conductivity of glass fiber insulation = 0.038 W/m-K

and thermal conductivity of gypsum wall board = 0.17 W/m-K

so resistance for wood is

resistance Rw = $\frac{0.008}{0.094*0.65*2.5}$ = 0.0549 K/W ................2

and resistance for stud is

resistance Rs = $\frac{0.100}{0.16*0.04*2.5}$ = 6.25 K/W ....................3

and resistance for insulation

resistance Ri = $\frac{0.100}{0.038*(0.65 - 0.04)*2.5}$ = 1.7256 K/W .................4

and resistance for wall board

resistance Rg = $\frac{0.012}{0.17*0.65*2.5}$ = 0.4343 K/W .................5

so here stud and insulated are parallel

so resistance = $( Rs^{-1} + Ri^{-1} )^{-1}$

we get resistance = $( 6.25^{-1} + 1.7256^{-1} )^{-1}$ = 1.3522 K/W ..........................6

so total resistance is

total resistance add equation 2 and equation 5 and 6

total resistance = 0.0549 + 0.4343 + 1.3522

total resistance = 1.8414 K/W

and

studs are 10

so total resistance will be

total resistance = $\frac{1.8414}{10}$

total resistance = 0.18414 K/W

7 0

4 years ago