Since you have notified the company that they were out of compliance with MS licensing requirement, the next thing to do is to look or ask for the product key that is with the company
The other information would you need is for the company to obtain the product license by buying the product key.
<h3>Do you need a license for Microsoft?</h3>
If you get to buy any of the standard Microsoft Office or other packages that is said to be the Home and Student edition, a person or firm will need a license.
Note that the license is one that guarantee one the use of the product and its installation.
Therefore You need to purchase a lot of copies of it and as such, Since you have notified the company that they were out of compliance with MS licensing requirement, the next thing to do is to look or ask for the product key that is with the company
The other information would you need is for the company to obtain the product license by buying the product key.
Learn more about MS licensing requirement from
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Answer:
0.867
Explanation:
The driver population factor ()can be estimated using the equation below:
The value of the heavy vehicle factor () is determined below:
The values of the = 2 and = 3 are gotten from the tables for the RVs, trucks and buses upgrades for passenger-car equivalents. Therefore:
= 1/[1+0.08(2-1)+0.06(3-1)] = 1/[1+0.08+0.12] = 1/1.2 = 0.833
Furthermore, the vp is taken as 2250 pc/(h*In) from the table of LOS criteria for lane freeway using the 15 minutes flow rate. Therefore:
= 3900/[0.8*3*0.833*2250] = 3900/4498.2 = 0.867
Answer:
A combination square is a multi-use measuring instrument which is primarily used for ensuring the integrity of a 90° angle, measuring a 45° angle, measuring the center of a circular object, find depth, and simple distance measurements. It can also be used to determine level and plumb using its spirit level vial.
Explanation:
Answer:
P ( 2.5 < X < 7.5 ) = 0.7251
Explanation:
Given:
- The pmf for normal distribution for random variable x is given:
f(x)=0.178 exp(-0.100(x-4.51)^2)
Find:
the fraction of individuals demonstrating a response in the range of 2.5 to 7.5.
Solution:
- The random variable X follows a normal distribution with mean u = 4.51, and standard deviation s.d as follows:
s.d = sqrt ( 1 / 0.1*2)
s.d = sqrt(5) =2.236067
- Hence, the normal distribution is as follows:
X ~ N(4.51 , 2.236)
- Compute the Z-score values of the end points 2.5 and 7.5:
P ( (2.5 - 4.51) / 2.236 < Z < (7.5 - 4.51 ) / 2.236 )
P ( -0.898899327 < Z < 1.337168651 )
- Use the Z-Table for the probability required:
P ( 2.5 < X < 7.5 ) = P ( -0.898899327 < Z < 1.337168651 ) = 0.7251