Answer:
3.61%
Step-by-step explanation:
This situation can be modeled with the Binomial Distribution which computes the likelihood of an event “success” that occurs exactly k times out of n, and is given by
where
= combination of n elements taken k at a time.
<em>p = probability that the event (“success”) occurs once
</em>
<em>q = 1-p
</em>
In this case, we define “success” as a college student not being confident that their major would lead to a good job.
Then
p = 49% = 0.49
q = 51% = 0.51
“If 15 college students are chosen at random, what's the probability that 11 of them are NOT confident that their major would lead to a good job?”
Here we are looking for P(11;15)
![\large P(11;15)=\binom{15}{11}0.49^{11}0.51^{(15-11)}=0.03611=3.61\%](https://tex.z-dn.net/?f=%5Clarge%20P%2811%3B15%29%3D%5Cbinom%7B15%7D%7B11%7D0.49%5E%7B11%7D0.51%5E%7B%2815-11%29%7D%3D0.03611%3D3.61%5C%25)