The value of the cosine ratio cos(L) is 5/13
<h3>How to determine the cosine ratio?</h3>
The complete question is added as an attachment
Start by calculating the hypotenuse (h) using
h^2 = 5^2 + 12^2
Evaluate the exponent
h^2 = 25 + 144
Evaluate the sum
h^2 = 169
Evaluate the exponent of both sides
h = 13
The cosine ratio is then calculated as:
cos(L) = KL/h
This gives
cos(L) =5/13
Hence, the value of the cosine ratio cos(L) is 5/13
Read more about right triangles at:
brainly.com/question/2437195
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Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
are in that situation pls tell me
Answer:
y= x-4
Step-by-step explanation:
Since we have a point, and the slope, we can use the point slope formula
m is the slope, y1 is the y coordinate of the point and x1 is the x coordinate of the point.
We know that m is 1, y1 is 1, and x1 is 5, so we can substitute them in
y-1=1(x-5)
Solve for y by isolating it
Distribute the 1
y-1=1*x+ 1*-5
y-1=x-5
Add 1 to both sides
y=x-4
