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kakasveta [241]
4 years ago
15

When 25.0 grams of water are cooled from 20.0 degrees Celsius to 10.0 degrees Celsius the number of joules of heat energy releas

ed is?
Chemistry
1 answer:
xxMikexx [17]4 years ago
4 0

Answer: 1045 J of energy was released on cooling the down the water from 20 °C to 10 °C.

Explanation:

Specific heat of water : 4.18J/g °C(standard value)

Q=mc\Delta T=

Q= Energy released

m = mass of the substance

c = specific heat value of a substance

\Delta T = Change in temperature

For 25 g of water the Q released when cooled down to 20 °C to 10 °C will be:

Q=mc\Delta T=25 g\times 4.18J/g ^oC\times (10^oC-20^oC)=-1045 J

Q = -1045 J (negative sign indicates that energy is released)

1045 J of energy was released on cooling the down the water from 20 °C to 10 °C.


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