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Rzqust [24]
3 years ago
6

If (fog)(x)=7x-1/3 and f(x)=3x+5,find g(x),where g(x)is linear​

Mathematics
1 answer:
Svetach [21]3 years ago
3 0

Answer: g(x) = \dfrac73x-\dfrac{16}{9}

Step-by-step explanation:

Given: (fog)(x)=7x-\dfrac13

f(x)=3x+5

and g(x) is linear.

A linear function is of the form : y= mx+c

Let g(x)= mx+c

Then, (fog)(x)=f(g(x))= f(mx+c)

= 3(mx+c)+5\\\\=3mx+3c+5

Comparing it with the original (fog)(x), we get

3mx+3c+5=7x-\dfrac{1}{3}

Comparing coefficient of x and constants separately

3m=7,\ \ \ \ 3c+5=-\dfrac13\\\\\Rightarrow\ m=\dfrac{7}{3},\ \ \ \ 3c =-\dfrac{1}{3}-5\\\\\Rightarrow\ m=\dfrac{7}{3},\ \ \ \ 3c =-\dfrac{16}{3}\\\\\Rightarrow\ m=\dfrac{7}{3},\ \ \ \ c =-\dfrac{16}{9}

So, g(x) = \dfrac73x-\dfrac{16}{9}

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To find two numbers that cover the same units from a given point on a number line, we can simply do the following:

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