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3 years ago

On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

Mathematics

1 answer:

nadezda [96]3 years ago

5 0

Answer:

Step-by-step explanation:

We can use the distance formula

d = sqrt ( ( y2-y1)^2 + ( x2-x1) ^2)

d = sqrt ( ( 4- -3)^2 + ( -4 -2) ^2)

= sqrt ( ( 7^2 + ( -6)^2)

= sqrt( 49+ 36)

= sqrt(85)

9.219544457

Rounding to the nearest whole number

= 9

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Which values of A and B make the following equations true?

Korolek [52]

(5x^7 y^2)(-4x^4 y^5) =-20x^a y^b

solve this:
(5x^7 y^2)(-4x^4 y^5)
= -20 x^(7 + 4) y^(2 + 5)
= -20 x^11 y^7

answer

A) a=11, b=7

5 0

3 years ago

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

Lilit [14]

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

$If\ a=b\ then\ a*c=b*c$

In this case, the equation that Jada had is the folllowing:

$-\frac{4}{9}=\frac{x}{108}$

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

$(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x$

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by $-\frac{4}{9}$ and the right side by $-\frac{9}{4}$ .

Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.

3 0

3 years ago

Read 2 more answers

The Surface Area of a square pyramid is 3600 ft. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot cu

amm1812

Answer:

10,583 flexible cubes

9915 rigid cubes

Step-by-step explanation:

The equation for the surface area of a square pyramid is area of base plus perimeter of base multiplied by the slant height

Surface area = A + 1/2·p·s

The volume of the pyramid = 1/3×A×h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30·√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, approximately 10,583 cubes

For rigid cubes we have

Given that the height of the pyramid = 30·√7

The slope of the pyramid = 30·√7/10 = 3·√7

So an increase in height of 1 foot gives a reduction in width of 2/(3·√7)

The bottom can hold 400 cubes

The next layer can hold 19×19 = 361

3rd 361

4th 361

5th 324

6th 324

7th 324

8th 324

9th

Continuing, we get a total of about 9915 rigid cubes in the pyramid.

3 0

3 years ago

Which relationship describes angles 1 and 2?

Crazy boy [7]

Supplementary angle.

5 0

3 years ago

nick is given 450 to sepend on a vacatio. he decides to spend $5 a day the amount nick has left and the number of days are relat

omeli [17]

Answer:

m= 450 - (5*n)

Step-by-step explanation:

m is the money left

n is the days

7 0

3 years ago