All categories

2 years ago

Help please!! 7&8 I don’t understand

Mathematics

1 answer:

Andrej [43]2 years ago

7 0

Answer:

7. 4

8. -2

Step-by-step explanation:

domain gose right so it should be 4 range goes down so it should be -2

You might be interested in

Matt said 2x-7=2(x-7) has infinitley many solitions. is he correct? Justify Matts answer or show he is correct.

Flauer [41]

2x - 7 = 2x - 14
2x = 2x - 7.

Matt is incorrect, there are actually 0 correct answers to this equation.

7 0

2 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

2 years ago

What is the quotation of -3/8 and -1/3

horrorfan [7]

Answer: A slash in between the numbers you put

Step-by-step explanation:

8 0

1 year ago

Read 2 more answers

Ratio reduced to the lowest form<br><br> 8 quarters to 30 dollars

chubhunter [2.5K]

Answer:

1:15

Step-by-step explanation:

there are 120 quarters in 30 dollars

so 8:120

divide both by 8

1:15

7 0

2 years ago

What are some practical applications of monomials

Andrews [41]

Answer:

A monomial is an expression in algebra that contains one term, like 3xy. Monomials include: numbers, whole numbers and variables that are multiplied together, and variables that are multiplied together. Any number, all by itself, is a monomial, like 5 or 2,700.

Step-by-step explanation:

5 0

3 years ago