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gulaghasi [49]
2 years ago
12

Help please!! 7&8 I don’t understand

Mathematics
1 answer:
Andrej [43]2 years ago
7 0

Answer:

7. 4

8. -2

Step-by-step explanation:

domain gose right so it should be 4 range goes down so it should be -2

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Matt said 2x-7=2(x-7) has infinitley many solitions. is he correct? Justify Matts answer or show he is correct.
Flauer [41]
2x - 7 = 2x - 14
2x = 2x - 7.

Matt is incorrect, there are actually 0 correct answers to this equation.
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2 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

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Step-by-step explanation:

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Answer:

1:15

Step-by-step explanation:

there are 120 quarters in 30 dollars

so 8:120

divide both by 8

1:15

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2 years ago
What are some practical applications of monomials
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Answer:

A monomial is an expression in algebra that contains one term, like 3xy. Monomials include: numbers, whole numbers and variables that are multiplied together, and variables that are multiplied together. Any number, all by itself, is a monomial, like 5 or 2,700.

Step-by-step explanation:

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