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3 years ago

A wire perpendicular to the screen carries a current in the direction shown.

Physics

2 answers:

mrs_skeptik [129]3 years ago

8 0

Answer:

A) Up

Explanation:

The direction of the current in the wire is going out of the screen. We can use the right-hand rule to find the direction of the magnetic field at point Z. In fact, we have to:

- Put the thumb of the right hand in the same direction as the current (out of the screen)

- Wrap the other fingers around the thumb. The direction of the fingers will be the same as the direction of the magnetic field.

By doing this procedure with out right hand, we see that the other fingers at point Z are directed up, so the magnetic field is also directed up.

____ [38]3 years ago

4 0

A) Up is the direction of the magnetic field at point Z.

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Inertia is responsible for :

DENIUS [597]

B. the reason we must wear seat belts

8 0

3 years ago

Read 2 more answers

How fast would a 2-kilogram object need to move to have the same kinetic

siniylev [52]

Answer:

11.3 m/s

Explanation:

KE₁ = KE₂

½m₁v₁² = ½m₂v₂²

½ (2 kg) v² = ½ (4 kg) (8 m/s)²

v ≈ 11.3 m/s

8 0

3 years ago

Salmon often jump waterfalls to reach their

natta225 [31]

Answer:

5.0 m/s

Explanation:

The horizontal motion of the salmon is uniform, so the horizontal component of the salmon's velocity is constant and it is

$v_x = u cos \theta$

where u is the initial speed and $\theta=37.7^{\circ}$ . The horizontal distance travelled by the salmon is

$d=v_x t = (ucos \theta)t$

where d = 1.95 m and t is the time needed to reach the final point.

Re-arranging for t,

$t=\frac{d}{v_x}=\frac{d}{u cos \theta}$ (1)

Along the vertical direction, the equation of motion is

$y=h+u_y t -\frac{1}{2}gt^2$

where:

y = 0.311 m is the final height reached by the salmon

h = 0 is the initial height

$u_y = u sin \theta$ is the vertical component of the initial velocity of the salmon

$g=9.81 m/s^2$ is the acceleration of gravity

t is the time

Substituting t as found in eq.(1), we get the equation

$y=(u sin \theta) \frac{d}{u cos \theta}- \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}$

and we can solve this formula for u, the initial speed of the salmon:

$y=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}\\\\u=\sqrt{\frac{gd^2}{2(dtan \theta -y)cos^2 \theta}}=\sqrt{\frac{(9.81)(1.95)^2}{2((1.95)(tan 37.7^{\circ}) -0.311)cos^2 37.7^{\circ}}}=5.0 m/s$