Answer:
Correct, is there another part to the question?
Answer:
2.1 rad/s
Explanation:
Given that,
Mass of a tether ball, m = 0.546 kg
Length of a rope, l = 4.56 m
The maximum tension the rope can withstand before breaking is 11.0 N
We need to find the maximum angular speed of the ball. Let v is the linear velocity. The maximum tension is balanced by the centripetal force acting on it. It can be given by :
![F=\dfrac{mv^2}{r}\\\\v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{11\times 4.56}{0.546}} \\\\=9.584\ m/s](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bmv%5E2%7D%7Br%7D%5C%5C%5C%5Cv%3D%5Csqrt%7B%5Cdfrac%7BFr%7D%7Bm%7D%7D%20%5C%5C%5C%5Cv%3D%5Csqrt%7B%5Cdfrac%7B11%5Ctimes%204.56%7D%7B0.546%7D%7D%20%5C%5C%5C%5C%3D9.584%5C%20m%2Fs)
Let
is the angular speed of the ball. The relation between the angular speed and angular velocity is given by :
![v=r\omega\\\\\omega=\dfrac{v}{r}\\\\=\dfrac{9.584}{4.56}\\\\=2.1\ rad/s](https://tex.z-dn.net/?f=v%3Dr%5Comega%5C%5C%5C%5C%5Comega%3D%5Cdfrac%7Bv%7D%7Br%7D%5C%5C%5C%5C%3D%5Cdfrac%7B9.584%7D%7B4.56%7D%5C%5C%5C%5C%3D2.1%5C%20rad%2Fs)
So, the maximum angular speed of the ball is 2.1 rad/s.
S: 198 m
v=39 m/s
u=0
t=?
a=?
v²=u²+2as
(39)²=(0)²+2(a)(198)
1521=396a
1521/396=a
3.84 m/s^2 = a
Hope I helped :)
Answer:
Explanation:
Yes , their displacement may be equal .
Suppose the displacement is AB where A is starting point and B is end point .
The car is covering the distance AB by going from A to B on straight line . On the other hand plane goes from A to C , then from C to D and then from D to B . In this way plane reaches B from A on a different path which is longer than path of the car . In the second case also displacement of plane is AB . In the second case distance covered is longer but displacement is same that is AB .
Answer:
This depends on the writers
if they want they can make spiderman deny the laws of nature