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amm1812
3 years ago
6

Hi math question is in the picture pls help

Mathematics
1 answer:
STatiana [176]3 years ago
4 0

Answer:

View Image. The red one is the answer

Step-by-step explanation:

Your first goal is to solve for x.

Once you have the inequality for x alone, graph both of it.

Only keep the parts where both inequality overlap each others.

You might be interested in
13,000 inches equals how many miles
Nataly [62]

Answer:

0.205177 mi

Step-by-step explanation:

Step 1: Find conversions

12 in = 1 ft

5280 ft = 1 mi

Step 2: Use Dimensional Analysis

13000 \hspace{2} in(\frac{1 \hspace{2} ft}{12 \hspace{2} in} )(\frac{1 \hspace{2} mi}{5280 \hspace{2} ft} )

0.205177 mi

8 0
2 years ago
A roller coaster begins at ground level, rises 63 feet, then falls 71 feet. What is the
meriva

Answer:

-8 feet

Step-by-step explanation:

63 - 71 = -8

3 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
10.5 equal or less than 10.005
maksim [4K]
10.5 is more than 10.005
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=10x-16y%3D12%20%5C%5C%205x-3y%3D4" id="TexFormula1" title="10x-16y=12 \\ 5x-3y=4" alt="10x-16y
Molodets [167]

Answer:

24/25

Step-by-step explanation:

Step 1: Define systems of equation

10x - 16y = 12

5x - 3y = 4

Step 2: Rewrite one of the equations

5x = 4 + 3y

x = 4/5 + 3y/5

Step 3: Solve for <em>y</em> using Substitution

  1. Substitute 2nd rewritten equation into 1: 10(4/5 + 3y/5) - 16y = 12
  2. Distribute the 10 to both terms: 40/5 + 30y/5 - 16y = 12
  3. Simplify the fractions down: 8 + 6y - 16y = 12
  4. Combine like terms (y): 8 - 10y = 12
  5. Subtract 8 on both sides: -10y = 4
  6. Divide both sides by -10: y = 4/-10
  7. Simply the fraction down: y = -2/5

Step 4: Substitute <em>y</em> back into an original equation to solve for <em>x</em>

  1. Substitute: 5x - 3(-2/5) = 4
  2. Multiply: 5x + 6/5 = 4
  3. Subtract 6/5 on both sides: 5x = 14/5
  4. Divide both sides by 5: x = 14/25

Step 5: Check to see if solution set (14/25, -2/5) is a solution.

  1. Substitute into an original equation: 10(14/25) - 16(-2/5) = 12
  2. Multiply each term: 28/5 + 32/5 = 12
  3. Add: 12 = 12

Here, we see that x = 14/25, y = -2/5 and solution (14/25, -2/5) indeed works.

Step 6: Find <em>x</em> <em>- y</em>

x = 14/25

y = -2/5

  1. Substitute: 14/25 - (-2/5)
  2. Simplify (change signs): 14/25 + 2/5
  3. Add: 24/25

Hope this helped! :)

6 0
3 years ago
Read 2 more answers
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