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Jobisdone [24]
4 years ago
5

What would be the resulting molarity of a solution made by dissolving 17.8 grams of LiF in enough water to make a 915-milliliter

solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
wariber [46]4 years ago
3 0
First, determine the amount of substance in moles by dividing the given amount in grams by the molar mass. 
              17.8 grams LiF x (1 mole / 25.94 grams LiF) = 0.686 moles LiF
Divide this amount of substance by the volume of the solution in liters.
                           molarity = 0.686 moles LiF / 0.915 L sol'n
The molarity is therefore, 0.75 M. 
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This is an example of redox titration.

Using titration formula:

CAVA/CBVA = NA/NB

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VA is the volume of Fe2+ = (30mL)

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NA is the numeric coefficient of Fe2+ in the equation of reaction = ( 5 )

NB is the numeric coefficient of MnO4- in the equation of reaction =(1)

Substituting the values into the formula;

0.134×30/CB×23.5 = 5/1

Therefore CB = 0.134×30/23.5×5

= 0.0342 M

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