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trapecia [35]
2 years ago
8

Are these physical or chemical changes?

Chemistry
2 answers:
Mnenie [13.5K]2 years ago
6 0
Chemical i pretty sure! please do more searching if u think i’m wrong.
Darya [45]2 years ago
5 0
All are chemicalllllllll
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If metal ions in a solution were reduced, what would you expect to see?
marysya [2.9K]

Answer:

Solid metal

Explanation:

The reduced form of metal ions is the metal in elemental state (simple substance). So, if you have a solution with metal ions and they are reduced, you probably will see the deposition of the metal. For example: if you have a solution with sodium ions (Na⁺), and the ions are then reduced, you will see the aparition of a solid phase of metallic sodium (Na(s)), according to the following half-reaction:

Na⁺ + e- → Na(s)

8 0
2 years ago
What can the student predict if she finds the mass of the whole candy bar, including the wrapper?
Vesna [10]

Answer:

A student can predict Amount of calories present if she finds the mass of whole candy bar,including the wrapper.

<u>Explanation:</u>

Based on the mass of a whole candy bar a student can predict the calories contained in the candy bar. If the mass of candy bar is more than it means it has more calories and if the candy bar has less mass than it shows the presence of fewer calories.

More calories mean more sugar content in the candy bar. With sugar, the candy bar has carbohydrates also. The sugar present in the bar gives us energy.

6 0
3 years ago
What compound does hydrogen form?​
Oxana [17]
It forms covalent compounds
6 0
3 years ago
Read 2 more answers
When the n quantum number equals 1, we are in what orbital?
g100num [7]

Answer:

p orbital

Explanation:

8 0
3 years ago
vaporized at 100°C and 1 atmosphere pressure. Assuming ideal gas 1 g mole of water is behavior calculate the work done and compa
Vesna [10]

Answer:

q = 40.57 kJ; w = -3.10 kJ; strong H-bonds must be broken.

Explanation:

1. Heat absorbed

q = nΔH = 1 mol × (40.57 kJ/1 mol) = 40.57 kJ

2. Change in volume

V(water) = 0.018 L

pV = nRT

1 atm × V = 1 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 373.15 K

V = 30.62 L

ΔV = V(steam) - V(water) = 30.62 L - 0.018 L = 30.60 L

3. Work done

w = -pΔV = - 1 atm × 30.60 L = -30.60 L·atm

w = -30.60 L·atm × (101.325 J/1 L·atm) = -3100 J = -3.10 kJ

4. Why the difference?

Every gas does 3.10 kJ of work when it expands at 100 °C and 1 atm.

The difference is in the heat of vaporization. Water molecules are strongly hydrogen bonded to each other, so it takes a large amount of energy to convert water from the liquid phase to the vapour phase.

7 0
3 years ago
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