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3 years ago

All three of the phosphorus-fluorine single bonds in pf3 are polar. in which direction should the polarity arrows point?

1 answer:

3 0

One of the causes of polarity is the unequal forces of the dipole forces due to differences in electronegativity. The more electronegative molecule tend to attract electrons, hence the polarity arrows point towards it. The electronegativity of Phosphorus and Fluorine is 2.19 and 3.98, respectively. Thus, it points outward towards the fluorine atoms.

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How will the price of a product impact on the profits of the entrepreneur

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Answer:

The higher your price, the less volume you have to produce for a given dollar amount of profit! Even a small price increase can generate significant additional profit. ... When a business comes out with a new product or service and they are the first to market, they may be able to charge high prices initially.

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2 years ago

True or false:The nucleus is the largest part of the atom and takes up most space

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It has the most mass. but the electron cloud takes up the most space.

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3 years ago

Dissolution of KOH, ΔHsoln:

swat32

Using Hess's law we found:

1) By adding reaction 10.2 with the reverse of reaction 10.1 we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) ΔH (10.3)

2) The ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy (ΔH).

The reactions of dissolution (10.1) and neutralization (10.2) are:

KOH(s) → KOH(aq) ΔHsoln (10.1)

KOH(s) + HCl(aq) → H₂O(l) + KCl(aq) ΔHneut (10.2)

1) According to Hess's law, the total change in enthalpy of a reaction resulting from differents changes in various reactions can be calculated as the sum of all the enthalpies of all those reactions.

Hence, to get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

We need to add reaction 10.2 to the reverse of reaction 10.1

KOH(s) + HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq) + KOH(s)

Canceling the KOH(s) from both sides, we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

2) The change in enthalpy for reaction 10.3 can be calculated as the sum of the enthalpies ΔHsoln and ΔHneut:

$\Delta H = \Delta H_{soln} + \Delta H_{neut}$

The enthalpy of reaction 10.1 (ΔHsoln) changed its sign when we reversed reaction 10.1, so:

$\Delta H = \Delta H_{neut} - \Delta H_{soln}$

Therefore, the ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy ΔH.

Learn more here:

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I hope it helps you!

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2 years ago

Banana dipped in liquid experiments

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Https://www.youtube.com/watch?v=LXDG0nqYdR4

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3 years ago

When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _

olya-2409 [2.1K]

Balancing redox reactions:

Oxygen should be balanced by adding $H_{2}O$ as needed, while hydrogen should be balanced by adding $H^{+}$ .

What is a redox reaction?

Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.

The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding $H_{2}O$ , $H^{+}$ , and $e^{-}$ in that order, each reaction is brought into equilibrium:

By putting the right number of water ( $H_{2}O$ ) molecules on the other side of the equation, the oxygen atoms are brought into balance.
By adding $H^{+}$ ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).
Total the fees for each side. Add enough electrons ( $e^{-}$ ) to the more positive side to make them equal. (As a general rule, $e^{-}$ and $H^{+}$ are nearly always on the same side.)
The $e^{-}$ on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.
One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.
Now that the equation has been verified, it can be balanced.

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2 years ago