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zloy xaker [14]
3 years ago
15

which pair shares the same empirical formula. c2h2 and c6h6, c2h2 and c2h4, ch2 and c6h6, ch and c2h4

Chemistry
1 answer:
olasank [31]3 years ago
7 0

Answer:

Answer: CH₃ and C₂H₆ have same empirical formula.

Explanation:

it just compares in that it its the same

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Which of the following characteristics is not a property of an acid?
s2008m [1.1K]
Increases the concentration of hydronium ions in an aqueous solution
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Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H1
nadya68 [22]

Answer:

\boxed{\text{B.}}

Explanation:

B.

\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O

NOT BALANCED. 7C on left and 6C on right.

C.

\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O

NOT BALANCED. 16H on left and 10H on right.

D.

\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O

NOT BALANCED. 7C on left and 14C on right.

3 0
3 years ago
Find the mass ratios and atomic ratios of the following compounds.
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3 years ago
Complete the following table. Tell if the molecule is polar or nonpolar, draw the Lewis dot structure for the molecule, tell wha
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The complete table is shown in figure

a) NH3 is polar as the bonds between N and H are polar. Due to asymmetry in   the molecule the molecule is polar

The shape of molecule is trigonal pyramidal while its electronic geometry is tetrahedral.

b) CO2: it is a non polar molecule with polar bonds. The molecule becomes non polar as the dipole moment cancel each other. [Dipole moment is a vector quantity]

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5 0
3 years ago
Read 2 more answers
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
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464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

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