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konstantin123 [22]
3 years ago
10

If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul

d have happened to the pressure of gas
Chemistry
2 answers:
LiRa [457]3 years ago
6 0

The pressure of the gas would increase.

Assoli18 [71]3 years ago
5 0

<u>Answer:</u>

Pressure of the gas increases.

<u>Explanation:</u>

If a gas is moved from a large container to a small one while its temperature and number of moles are kept constant, then the pressure of the gas would increase.

We can use the ideal gas equation to prove this.

PV = NRT

According to this equation, when the volume of the gas is decreased while the temperature and the number of moles are constant, then the pressure of the gas increases.

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Arrange these elements in order of decreasing atomic size:sulfur, chlorine, aluminium, and sodium.​
Alborosie

Answer:

Sodium,aluminium,sulfur and chlorie

7 0
3 years ago
what volume, in liters, will 6.32 × 10^2 of air occupy if the density of air is 1.29 g/L? Express your answer in scientific nota
xz_007 [3.2K]

4.90× 10^2 L

I am guessing that the mass of the air is 6.32 × 10^2 <em>g</em>. Then,

Volume = 6.32 × 10^2 g × (1 L/1.29 g) = 4.90× 10^2 L

3 0
3 years ago
Read 2 more answers
12. If the total pressure exerted by 3 gases is 45 atm and each individual gas has the
Bumek [7]

Answer:

Partial pressure for each of the three gases, in the mixture is 15 atm

Explanation:

Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.

Our total pressure = 45 atm

The 3 gases have the same pressure, so we can propose this equation:

3x = 45 atm

where x is the partial pressure for each of the three gases.

x = 45/3 → 15 atm

3 0
3 years ago
The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b
Angelina_Jolie [31]
Let's begin with the basic values  that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(
C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (
ΔHc°).  

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) 
ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.



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