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konstantin123 [22]
3 years ago
10

If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul

d have happened to the pressure of gas
Chemistry
2 answers:
LiRa [457]3 years ago
6 0

The pressure of the gas would increase.

Assoli18 [71]3 years ago
5 0

<u>Answer:</u>

Pressure of the gas increases.

<u>Explanation:</u>

If a gas is moved from a large container to a small one while its temperature and number of moles are kept constant, then the pressure of the gas would increase.

We can use the ideal gas equation to prove this.

PV = NRT

According to this equation, when the volume of the gas is decreased while the temperature and the number of moles are constant, then the pressure of the gas increases.

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Which of the following pairs of substances form a buffer system for human blood?
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Answer:

d. Because those chemicals are easily made when CO2 reacts with water, forming H2CO3 (via carbonic anhydrase

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2 years ago
Use your calculator to determine the answer to the following calculation:<br> 1.0×10^−15/4.2×10^−7
lianna [129]
1.0×10^−15/4.2×10^−7=<span>2.3809524e-23 Hoped I helped!</span>
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3 years ago
Group 8A of the periodic table contains the A. most reactive nonmetals. B. least reactive nonmetals. C. most reactive metals. D.
aivan3 [116]

Answer: The correct answer is option B.

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7 0
2 years ago
Read 2 more answers
A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol
astraxan [27]

Answer:

Volume of the CO_{2} gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

\frac{V}{T} =\frac{v}{t}

where , V= initial volume          v= final volume

             T=initial temperature    t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K                      (since converting celsius into kelvin that

                                                         is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

\frac{240ml}{295K} =\frac{v}{317K}

240ml x317K = v x 295K     (through cross multiplication )

v =\frac{240ml\times317K}{295K}

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

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