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murzikaleks [220]
3 years ago
10

Estimate the value of √2π/√5

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer: 1.12099824328 or estimated is 1

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If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.
Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

<em></em>

Step-by-step explanation:

Given

f(x)=x^3-12x^2+35x-24

f(8) = 0

Required

Find all zeros of the f(x)

If f(8) = 0 then:

x = 8

And x - 8 is a factor

Divide f(x) by x - 8

\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}

Expand the numerator

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}

Rewrite as:

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}

Expand

\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}

\frac{f(x)}{x - 8} = (x - 1)(x - 3)

Multiply both sides by x - 8

f(x) = (x - 1)(x - 3)(x - 8)

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

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2 years ago
Is this tangent to the circle?
erica [24]
Hello,

Yes since (2*6.4)²+9.6²=256=16²
Angle A=90°
5 0
3 years ago
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What is 913 rounded to the nearest hundred
mixer [17]
If i mean .913 then .91 but if u wrote it correctly then 900
8 0
3 years ago
What is the remainder when (4x3 + 2x2 − 18x + 38) ÷ (x + 3)?<br> 2<br> 12<br> 96<br> 110
Brilliant_brown [7]
°°°4°°°2°°°-18°°°°°°38
•|
-3|°°°-12°°°30°°°°°-36
------------------------------'
°°°4°° -10 12°°°°° °°2
remainder=2
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2605 rounded to the nearest hundred
Fittoniya [83]
It would round to 2600
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