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Zarrin [17]
3 years ago
14

999 to the 2nd power. first person gets 99 points.

Mathematics
2 answers:
Mashcka [7]3 years ago
8 0

999 to the 2nd power

999^2 =

998001

Answer: 998001

Tasya [4]3 years ago
6 0
999 to the 2nd power = 999x999
999x999=998001
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A chef uses 8 1/2 cups flour for his gig nine 3/4 cup flour for his pies and 25 2/3 cups flour for his bread will he have any fl
katen-ka-za [31]

Answer:

50-25 2/3 - 9 3/4 - 8 1/2 = 6 1/12

Step-by-step explanation:

To do this without a calculator you need to get common denominator

a good choice would be 12 for the common denominator

50 x 12 = 600

25 x 12 = 300

convert to 2/3 to x/12, multiply top and bottom by 4

2/3 x 4 = 8/12

add this to the 300 to get 308/12

same with the other terms

9 x 12 = 108

convert 3/4 to x/12, multiply top and bottom by 3

3/4 x 3 = 9/12

add this to the 108 to get 117/12

and do the same for the 8 1/2

8x 12 = 96

convert 1/2 to x/12, multiply top and bottom by 6

1/2 = 6/12, add this to the 96

do the subtraction and simplify

8 0
3 years ago
F(x)=-2(x-3)(x+5) convert quadratic functions to standard form​
jasenka [17]

Answer:

The answer is: f(x) = -2x^2 - 4x + 30

Step-by-step explanation:

Given:

f(x)=-2(x-3)(x+5)

Solve (x-3)(x+5) first, then multiply by -2:

f(x) = -2[(x - 3)(x + 5)]

f(x) = -2[x^2 -3x + 5x - 15]

f(x) = -2[x^2 + 2x - 15]

f(x) = -2x^2 - 4x + 30

Hope this Helps!! Have an Awesome Day!! (-:

4 0
3 years ago
I need to know the answer
guapka [62]
9! good luck skdjdjd
4 0
3 years ago
Read 2 more answers
Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m
castortr0y [4]

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

v=\sqrt{\dfrac{Gm}{r}}

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

m_E=6. 0 \times10^{24} kg

The value of gravitational constant is,

G=6. 67\times 10{-11}\rm Nm^2/kg^2

The radius of the earth is,

r_E=6. 0 \times 10^6 \rm m

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

7 0
3 years ago
Add 2f+5g+7h and 3f+6g+8h
Kruka [31]
5f+11g+15h



Explanation:

2f+5g+7h+3f+6g+8h

You just combine the like terms
5f+11g+15h
6 0
3 years ago
Read 2 more answers
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