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spayn [35]
3 years ago
10

The farthest distance a satellite signal can directly reach is the length of the segment tangent to the curve of Earth's surface

. The diagram is not drawn to scale.
If the angle formed by the tangent satellite signal is 154°, what is the measure of the intercepted arc on Earth?
26°
52°
77°
308°

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0
To solve the question, we draw a circle representing a great-circle section of the earth, with satellite at a point S above earth. Draw tangents from S to he circle, and from points A and B, to the center C.
Hence:
AC and BC are radii, and
SA⊥AC and SB⊥BC
∠ASB=154°
making the angular measure of the intercepted arc:
∠ACB=180-154=26°

Answer: 26°
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order of operation

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Two friends Ana and Juan are buying books by joining the History Book
Travka [436]

Answer:

Ana  spent $17  per book on average.

Juan  spent $14.78  per book on average.

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Step-by-step explanation:

Ana has to pay a yearly fee of $15 to join.

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The amount spent on books = Total amount - yearly fee

                                                 = $525- $15= $510

Price per book on the average = $510/30= $ 17

Ana  spent $17  per book on average.

Juan has to pay a yearly fee of $10 to join.

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The amount spent on books = Total amount - yearly fee

                                                 = $350- $10= $340

Price per book on the average = $340/23= $ 14.78≅ $15

Juan  spent $14.78  per book on average.

The function can be established if y gives the total cost and x gives the number of books

y = $15 + 17x--------- equation 1

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Juan has a better deal because the yearly fee is less also the price per book is less.

8 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

Parameterize <em>S</em> by the vector-valued function <em>r</em>(<em>u</em>, <em>v</em>) defined by

\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

d<em>S</em> = <em>n</em> • d<em>S</em>

where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

4 0
4 years ago
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LenKa [72]

Answer:

\frac{1}{4}

Step-by-step explanation:

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Then

the possibility that the money will be in the next pocket :

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7 0
2 years ago
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