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riadik2000 [5.3K]
3 years ago
10

A coffee pot holds 4 1/4 quarts of coffee. How much is this in cups?

Mathematics
2 answers:
Vlad [161]3 years ago
8 0
There are 17 cups in 4 and 1/4 quarts
SSSSS [86.1K]3 years ago
4 0
4 1/4 quarts is 17 cups.
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Volgvan
Sorry I don’t get that one
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3 years ago
Matrix A = [6 -12 4 8]. What is matrix X if 1/2x=A?
Step2247 [10]

Answer:

X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right]

Step-by-step explanation:

A matrix is given by

A = \left[\begin{array}{cccc}6&-12&4&8\end{array}\right]

Now, we have to find the matrix X if \frac{1}{2} X = A

⇒ X = 2A

Now, multiplication of a constant with a matrix means multiplication with that constant with all the terms of the matrix.

So, X = \left[\begin{array}{cccc}6 \times 2&-12 \times 2&4 \times 2&8 \times 2\end{array}\right]

⇒ X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right] (Answer)

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3 years ago
Read 2 more answers
Part A: Larry earned $11 walking his neighbors' dogs on Saturday. He earned some extra money on Sunday doing the same thing. Wri
djyliett [7]
So for part a the answer with be 11/6
Why 6 because count the weeks that wil be 6 so Monday Tuesday Wednesday thursaday and Friday then comes Saturday
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3 years ago
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What is the geometric mean og 6 and 13
lara31 [8.8K]

Answer:

The answer is

Step-by-step explanation:

6 0
2 years ago
4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B
AleksAgata [21]

Answer:

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

8 0
3 years ago
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