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Leona [35]
3 years ago
12

One method of removing phosphate from wastewater effluents is to precipitate it with aluminum sulfate. A plausible stoichiometry

(but not exact because aluminum and phosphate can form many different chemical materials) is:
Chemistry
1 answer:
Viktor [21]3 years ago
8 0

Answer: The equation is written below.

Explanation:

2PO_4^{3-}(aq)+Al_2(SO_4)_3(aq)\rightarrow 2AlPO_4(s)+3SO_4^{2-}(aq)

According to Stoichiometry of the reaction:

2 moles of phosphate ions reacts with 1 mole of aluminum sulfate to produce 2 moles of aluminum phosphate precipitate and 3 moles of sulfate ions.

Aluminum phosphate is an odorless and white crystalline solid

The chemical equation is written above.

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suppose the mass spectrum of a hypothetical monatomic element X contains a signal at mass number 13 and another of identical hei
Illusion [34]
Average the numbers 13 and 15 to get 14amu.
6 0
3 years ago
1) Which of the following is the smallest unit of a chemio<br> Tallest unit of a chemical element?
solong [7]

Answer:

Nanomachines will work with atoms, not nuclei. The smallest unit of a chemical element, about a third of a nanometer in diameter. Atoms make up molecules and solid objects.

Explanation:

6 0
3 years ago
in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
kolezko [41]

Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5

mol of element G :

\tt mol=\dfrac{4}{16}=0.25

mol ratio A : G = 0.5 : 0.25 = 2 : 1

4 0
2 years ago
If a car travels 400.0 meters in 20.0 seconds, how fast is it going?<br> m/s<br> Please help me
Viefleur [7K]

Answer:

20m/s.

Explanation:

8 0
3 years ago
'Suppose you take 0.0332 kg of ammonium carbonate and dissolve it using 0.0395 kg of water. What would be the mass percent conce
VMariaS [17]

The solution is 45.7 % (NH₄)₂CO₃ by mass.

Mass of solution = 0.0332 kg + 0.0395 kg = 0.0727 kg

% (NH₄)₂CO₃ = Mass of (NH₄)₂CO₃/Total mass × 100 % = 0.0332 kg/0.0727 kg × 100 % = 45.7 %


8 0
3 years ago
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