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ahrayia [7]
3 years ago
12

It contains only one type of molecule or extended structure.

Chemistry
1 answer:
Gelneren [198K]3 years ago
6 0
What’s the question though
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Approximately 2.5 kg of carbon dioxide gas are produced for every liter of gasoline burned in an automobile gasoline engine. Cal
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125 mile *1gallon/35 mi = 135/35 = (27/7) gallon gasoline 

27/7 gallon * 1 L/0.264 gallon = 14.6 L  gasoline

14.6 L gasoline * 2.5kg CO2/1L gasoline= 36.5 kg CO2

36.5 kg CO2 * 1lb/0.454 kg = 80.4 lb

Answer: 80.4 lb CO2

6 0
3 years ago
When preparing a buret for use in lab, the buret must always be cleaned thoroughly. prior to being filled with solution, the bur
erastova [34]
It is rinsed one last time with the solution to be measured because if there is water in the burret, then it could alter the results. Slightly, but it is still altering it.
6 0
3 years ago
HELPP
Natasha_Volkova [10]
I’m pretty sure it’s D.increases the activation energy for a reaction.
4 0
3 years ago
How many atoms are in 3.05 grams of copper?
vfiekz [6]

6.02 x10^23 atom  

3.5g x 1mol/63.55g Cu x 6.02 x 10^23/ 1mol=

3.32 x 10^22 atoms

5 0
3 years ago
A 5.00 L sample of air at 0 C is warmed to 100.0 C. What is the new volume of the air? First, identify V1.
Paladinen [302]

Answer : The new volume of the air is, 6.83 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=5.00L\\T_1=0^oC=(0+273)K=273K\\V_2=?\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{5.00L}{273K}=\frac{V_2}{373K}\\\\V_2=6.83L

Therefore, the new volume of the air is, 6.83 L

6 0
4 years ago
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