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2 years ago

If I have 0.070 moles of gas at a pressure of 0.20 atm and at a temperature of 8.00°C,

Chemistry

1 answer:

Ivanshal [37]2 years ago

3 0

Answer:

PV=nRT

0.20×v = 0.070×8.00

0.20V= 0.56

0.20v÷0.20v = 0.56÷0.20v

= 2.8

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Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce

Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{3.49}{3.50}=0.997g$

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{9.00}{6.00}=1.5g$

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

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3 years ago

Give the mass percent of carbon in C14H19NO2?

Pachacha [2.7K]

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3 years ago

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spayn [35]

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2 years ago

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miss Akunina [59]

Answer:

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2 years ago

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Lunna [17]

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3 years ago

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