The sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11
<h3>Sum of expressions</h3>
Expressions are equations separated by mathematical signs. This expressions are known to contains certain unknowns
Given the following expression
10x^2 +7x+6 and 6x + 5
We are to take the sum of both expression to have:
f(x) = 10x^2 +7x+6 + 6x + 5
Collect the like terms
f(x) = 10x^2 + 7x + 6x + 6 + 5
f(x) = 10x^2 + 13x + 11
Hence the sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11
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Answer:
x + y = 125
3.50x + 2.25y = 347.50
53 rolls
Step-by-step explanation:
System of equations
so basically if we say that rolls are represented by x and wrapping paper is represented by y, we can say x plus y is 125 because there are a total of 125 rolls and packages. if each roll is 3.50 and each package is 2.25, we can just put each number in front of the corresponding variable to show that each one is worth that amount, and they total to 347.50. then you have to solve the system of equations. so if you solve for x in the first equation, x = 125 - y. so plug that in to the next equation, 3.50(125 - y) + 2.25y = 347.50. solve for y and you get 72.
but y is the number of packages, and we want the number of rolls. there are 125 rolls and packages, so 125 minus the 72 packages and you get 53 rolls
41 Fahrenheit is 5 Celsius
Based on the information given, the true statement true about their gas-price data is A. Raquel’s data are most likely closer to $3.42 than Van’s data are to $3.78.
<h3>
Solution to the gas-price data.</h3>
It should be noted that a standard deviation simply measures how dispersed the data will be in relation to the mean.
From the complete question, the mean of Raquel's data is given as 3.42 while the standard deviation is given as 0.07. On the other hand, the mean of Van's data is given as 3.78 while the standard deviation is given as 0.23.
Therefore, it can be deduced that Raquel’s data are most likely closer to $3.42 than Van’s data are to $3.78.
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