Question

What is the product? (4y − 3)(2y2 + 3y − 5)

Answer 1

Answer:  The required product is $8y^3+6y^2-29y+15.$

Step-by-step explanation:  We are given to find the following product :

$P=(4y-3)(2y^2+3y-5).$

To find the given product, we need to multiply each term of the first expression to each term of the second expression.

The multiplication is as follows :

$P\\\\=(4y-3)(2y^2+3y-5)\\\\=4y(2y^2+3y-5)-3(2y^2+3y-5)\\\\=8y^3+12y^2-20y-6y^2-9y+15\\\\=8y^3+6y^2-29y+15.$

Thus, the required product is $8y^3+6y^2-29y+15.$

Answer 2

All ya got to do is break is down

Step 1) 4y(2y2+3y-5)-3(2y2+3y-5)
Step 2) 8y3+12y2-20y-3(2y2+3y-5)
Step 3) 8y3+12y2-20y-(6y2+9y-15)
Step 4) 8y3+12y2-20y-6y2-9y+15
Step 5) 8y3+(12y2-6y2)+(-20y-9y)+15

Then you got to simplify and you have to

Leave the

8y3 +

12-6= number y2 -

-20-9=- number y

Then leave the 15



Sorry your doing the same math as me so I get carried away :p