Ask question

Ask question

All categories

kondor19780726 [428]

3 years ago

10

Percent sales tax: 7% price before tax: $250 price with tax:

2 answers:

Likurg_2 [28]3 years ago

7 0

Answer:

idk

Step-by-step explanation:

Tamiku [17]3 years ago

4 0

7% as a decimal is 0.07. Multiply 0.07x250. You get 17.50. This is the tax, not the final price. For that, add 17.5 to 250. The price with tax is $267.50

You might be interested in

. In April, it rained 1/4 of an inch on 15 different days. How many inches of rain fell

notka56 [123]

Answer:

3.75, or $\frac{15}{4}$ inches of rain during the 15 days of April.

Step-by-step explanation:

All you have to do is add $\frac{1}{4}$ 15 times to get that number.

$\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ = 3.75

You can also do 15 times $\frac{1}{4}$ , which will result in the same thing.

#teamtrees #WAP (Water And Plant)

5 0

3 years ago

Evaluate for this problem <br> Help!!!

RoseWind [281]

${a}^{2} - b + 2c$
${5}^{2} - 17 + 2 \times 2$
$25 - 17 + 4$
PEMDAS
$25 - 21$
$4$

7 0

3 years ago

Passing through (2, - 2) and perpendicular to the line whose equation is y= 5x+2

jonny [76]

Step-by-step explanation:

Hey there!!!

Here,

Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.

The equation of a straight line passing through point is,

$(y - y1) = m1(x - x1)$

Now, put all values.

$(y + 2) = m1(x - 2)$

It is the 1st equation.

Another equation is;

y = 5x +2........(2nd equation).

Now, Comparing it with y = mx + c, we get;

m2=5

As per the condition of perpendicular lines,

m1×m2= -1

m1 × 5 = -1

Therefore, m2= -1/5.

Keeping the value of m1 in 1st equation.

$(y + 2) = \frac{ - 1}{5} (x - 2)$

Simplify them.

$5(y + 2) = - x + 2$

$5y + 10 = - x + 2$

$x + 5y + 8 = 0$

Therefore the required equation is x+5y+8= 0.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0

4 years ago

In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

3 years ago

WILL GIVE BRAINLIEST PLEASE HELP AND THANK YOU IF YOU DO HELP!!!!!

Gnesinka [82]

If 1 in.= 2.54 cm, Then !9in. multiplied by 2.54 cm would be b. 48.26 cm

6 0

4 years ago

Read 2 more answers