Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
Answer:
h = 9 units of length
Step-by-step explanation:
Volume of a circular right cone is:
V(c) = (1/3)*Area of the circular base * h
Where h is the height of the cone, then
V(c) = (1/3) * π * r² * h
And we have that V(c) = 108*π
Then:
108 * π = (1/3) * π * r² * h (1)
We know diameter of the circular base is 12 units, according to that
r = d/2 ⇒ r = 12/2 r = 6 units
Then:
108 * π [ cubic units ] = (1/3) * π * (6)² * h [square units] [ units of length]
When simplifying we have to take into account that in order to keep last equation h needs to have units of length
Therefore:
108 = (1/3) * 36 * h
h = ( 108* 3 )/ 36
h = 9 units of length
I think the answer might be <em>B 30.4 ft</em> if it not it might be <em>C 161 ft</em>
pls correct me if i'm wrong sorry if the answers is wrong
Does the question include a picture?
