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erastova [34]
4 years ago
8

Please, I need help!!

Physics
1 answer:
Masja [62]4 years ago
8 0

The box has weight 50.0 N (a downward force), from which we can determine its mass m:

-50.0\,\mathrm N=m(-g)=m\left(-9.80\,\dfrac{\mathrm m}{\mathrm s^2}\right)\implies m=5.10\,\mathrm{kg}

The box's acceleration is taken to be uniform, which means its acceleration due to the frictional force (which acts in the leftward direction) at any time during the \Delta t=t_2-t_1=2.25\,\mathrm s interval is

\vec a=\dfrac{0-1.75\,\frac{\mathrm m}{\mathrm s}}{2.25\,\mathrm s}=-0.778\,\dfrac{\mathrm m}{\mathrm s^2}

Then the friction force has magnitude F (where the vector is acting in the leftward direction) satisfies

\vec F=m\vec a\implies-F=(5.10\,\mathrm{kg})\left(-0.778\,\dfrac{\mathrm m}{\mathrm s^2}\right)\implies F=3.97\,\mathrm N

and the closest answer would be A.

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